sed - 如果找到，如何根据模式获取特定行

Question

我试图从一个非常大的文件中收集文件名，具体取决于特定用户，在这种情况下 windowsdom\nasarchive被发现。

我试过运行 sed -nr "/-{3,}/h; /Path\s*:/H; /windowsdom\\nasarchive\s+Allow\s+FullControl/{x;G;p}" logfilename但它不会带来任何东西。

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Path: U:\Credit share\BI-WEEKLY CREDIT NOTES\2010\Credit status - April 21 - 2.doc


AccessToString : windowsdom\nasarchive Allow  FullControl
                 BUILTIN\Administrators Allow  FullControl
                 NT AUTHORITY\SYSTEM Allow  FullControl
                 BUILTIN\Users Allow  ReadAndExecute, Synchronize

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Path: U:\Credit share\BI-WEEKLY CREDIT NOTES\2009\Credit status - Sept. 23 - 59.doc


AccessToString : windowsdom\acl_1 Allow  ReadAndExecute, Synchronize
                 windowsdom\acl_2 Allow  Modify, Synchronize
                 windowsdom\acl_3 Allow  ReadAndExecute, Synchronize
                 windowsdom\adm_server Allow  Modify, Synchronize
                 BUILTIN\Administrators Allow  FullControl


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Path: U:\Credit share\BI-WEEKLY CREDIT NOTES\2010\Credit status - August 10 - 3.doc


AccessToString : windowsdom\nasarchive Allow  FullControl
                 BUILTIN\Administrators Allow  FullControl
                 NT AUTHORITY\SYSTEM Allow  FullControl
                 BUILTIN\Users Allow  ReadAndExecute, Synchronize



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预期结果:

Path: U:\Credit share\BI-WEEKLY CREDIT NOTES\2010\Credit status - April 21 - 2.doc
Path: U:\Credit share\BI-WEEKLY CREDIT NOTES\2010\Credit status - August 10 - 3.doc 

有人能想出如何得到预期的结果吗？

Answer 1

这可能对你有用(GNU sed):

sed -rn '/^Path:/h;/windowsdom\\nasarchive\s+Allow\s+FullControl/{g;p}' file

这将打印最后一个 Path string 当遇到所需的字符串时。