我在测试 Reflux 操作是否在我的应用程序中正确触发时遇到了困难,实际上它们似乎根本不适用于 Jest。我有这个示例测试:
jest.autoMockOff();
describe('Test', function () {
it('Tests actions', function () {
var Reflux = require('../node_modules/reflux/index');
var action = Reflux.createAction('action');
var mockFn = jest.genMockFn();
var store = Reflux.createStore({
init: function () {
this.listenTo(action, this.onAction);
},
onAction: function () {
mockFn();
}
});
action('Hello World');
expect(mockFn).toBeCalled();
});
});
哪些输出:
● Test › it Tests actions
- Expected Function to be called.
at Spec.<anonymous> (__tests__/Test.js:20:20)
at Timer.listOnTimeout [as ontimeout] (timers.js:112:15)
即使使用 Jasmine 异步函数,它似乎也不起作用
jest.autoMockOff();
describe('Test', function () {
it('Tests actions', function () {
var Reflux = require('../node_modules/reflux/index');
var action = Reflux.createAction('action');
var mockFn = jest.genMockFn();
var flag = false;
var store = Reflux.createStore({
init: function () {
this.listenTo(action, this.onAction);
},
onAction: function () {
mockFn();
flag = true;
}
});
runs(function () {
action();
});
waitsFor(function () {
return flag;
}, 'The action should be triggered.', 5000);
runs(function () {
expect(mockFn).toBeCalled();
});
});
});
给我...
FAIL __tests__/Test.js (6.08s)
● Test › it Tests actions
- Throws: [object Object]
有没有人做过这个工作?
最佳答案
我想到了!我只需要使用 Jest 自己的方法来快速转发任何计时器。即只需添加行
jest.runAllTimers();
所以我的第一个例子的工作版本是
jest.autoMockOff();
describe('Test', function () {
it('Tests actions', function () {
var Reflux = require('../node_modules/reflux/index');
var action = Reflux.createAction('action');
var mockFn = jest.genMockFn();
var store = Reflux.createStore({
init: function () {
this.listenTo(action, this.onAction);
},
onAction: function () {
mockFn();
}
});
action('Hello World');
jest.runAllTimers();
expect(mockFn).toBeCalled();
});
});
关于jasmine - 如何使用 Jest 测试回流 Action ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28463189/