我有一个这样的数据集
4 6 18 12 4 5
2 9 0 3 NA 13
11 NA 6 7 7 9
如何使用 R 填充缺失值？
最佳答案
如果你想用固定值替换你的 NAs(a 是你的数据集):
a[is.na(a)] <- 0 #For instance
如果你想用一个作为行号和列号函数的值替换它们(正如你在评论中所建议的那样):
#This will replace them by the sum of their row number and their column number:
a[is.na(a)] <- rowSums(which(is.na(a), arr.ind=TRUE))
#This will replace them by their row number:
a[is.na(a)] <- which(is.na(a), arr.ind=TRUE)[,1]
#And this by their column number:
a[is.na(a)] <- which(is.na(a), arr.ind=TRUE)[,2]
关于r - 填充缺失值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13234005/