假设我有以下数据框:
DF1 <- data.frame("A" = rep(c("A","B"), 18),
"B" = rep(c("C","D","E"), 12),
"NUM"= rep(rnorm(36,10,1)),
"TEST" = rep(NA,36))
DF2 <- data.frame("A" = rep("A",6),
"B" = rep(c("C","D"),6),
"VAL" = rep(c(1,3),3))
*注:每个唯一的变量组合
A
和 B
在 DF2
应该有一个唯一的 VAL
.对于每一行,我想替换
NA
在 TEST
对应的值为 VAL
在 DF1
如果列中的值 A
和 A
匹配和列中的值 B
和 B
匹配该行。否则,我会离开 TEST
如 NA
.如果不使用 match 循环遍历每个组合,我将如何做到这一点?理想情况下,答案将扩展到两个数据框,其中包含许多要匹配的列。
最佳答案
# this is your DF1
DF1 <- data.frame("A" = rep(c("A","B"), 18),
"B" = rep(c("C","D","E"), 12),
"NUM"= rep(rnorm(36,10,1)),
"TEST" = rep(NA,36))
#this is a DF2 i created, with unique A, B, VAL
DF2 <- data.frame("A" = rep(c("A","B"),3),
"B" = rep(c("C","D","E"),2),
"VAL" = rep(1:6))
# and this is the answer of what i assume you want
tmp <- merge(DF1,DF2, by=c("A","B"), all.x=TRUE, all.y=FALSE)
DF1[4] <- tmp[5]
关于r - 如何使用多列作为键合并两个数据框?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29212691/