sql - ORA-01438 : value larger than specified precision allows for this column - How do i get which column it is referring to?

Question

我们是否有任何标准的 oracle 错误表或任何东西来识别我输入的值大于指定精度的表中的哪一列。
ORA-01438: value larger than specified precision allows for this column - 我如何获得它所指的列？

Answer 1

我觉得你得写个程序，试着一一更新专栏。

假设您有这样的更新:

UPDATE TABLE_1 a SET (COL_1, COL_2, COL_3) = 
   (SELECT COL_1, COL_2, COL_3 FROM TABLE_2 b WHERE a.COL_ID = b.COL_ID);

然后你可以通过这个循环遍历所有列:

DECLARE
    CURSOR TabColumns IS 
    SELECT column_id, column_name, data_precision, data_scale
    FROM USER_TAB_COLUMNS 
    WHERE table_name = 'TABLE_2'
       AND column_name <> 'COL_ID'
    ORDER BY 1;

BEGIN
    FOR aCol IN TabColumns LOOP
    BEGIN 
        sqlstr := 
            'UPDATE TABLE_1 a SET '||aCol.column_name ||' = '
                ||' (SELECT '||aCol.column_name ||
                ||' FROM TABLE_2 b '
                ||' WHERE  a.COL_ID = b.COL_ID)'

            EXECUTE IMMEDIATE sqlstr USING CalcDate, CalcDate;
    EXCEPTION
        WHEN OTHERS THEN
            DBMS_OUTPUT.PUT_LINE ( 'Error at column '|| aCol.column_id||CHR(9)|| aCol.column_name||CHR(9)||SQLERRM);
            DBMS_OUTPUT.PUT_LINE ( sqlstr );
    END;
    END LOOP;

END;    

效率不高，您应该会看到错误。