sql - 数据透视 SQL 查询 - 在列中显示日期

Question

我当前的查询返回以下结果

我需要的是必须在列标题中显示日期。我知道必须使用 Pivot

来完成

示例:如果我们想在列标题中显示月份，那么查询将类似于..

SELECT  [January], [February], [March]
FROM    ( SELECT    [Month], SaleAmount
          FROM      Sales
        ) p PIVOT ( SUM(SaleAmount)
                    FOR [Month] 
                      IN ([January],[February],[March])
                  ) AS pvt

我认为我的结果查询应该看起来像 Pivot ( (Price) FOR [DateVal] IN (What will be here?) ) 结果列应该是这样的

注意:结果集中目前显示的是12月份的数据，但可以是任意月份。

感谢您的帮助...

Answer 1

更新 4 好的，现在您已经发布了所有查询，并根据您的评论，您应该试试这个:

DECLARE @FirstDay SMALLDATETIME
SELECT @FirstDay = CONVERT(SMALLDATETIME, (@year + '-' + @month + '-01')); 

WITH Dates AS  
(
  SELECT @FirstDay AS DateVal 
  UNION ALL 
  SELECT DATEADD(d, 1, DateVal) AS DateVal 
  FROM Dates 
  WHERE DATEADD(d, 1, DateVal) < DATEADD(m, 1, @FirstDay)
)

SELECT * INTO #Dates FROM Dates

DECLARE @hotelID INT, @packageID INT, @year VARCHAR(4), @Dates VARCHAR(1000), @month VARCHAR(2), @Query VARCHAR(MAX)
SELECT @hotelID=248, @packageID=76, @year='2010', @month='12',@Dates=''

SELECT co.*,wb.Name,rc.HotelName 
INTO #HotelData
FROM RCompetitorOccupancy co 
INNER JOIN websites wb ON wb.websiteid=co.websiteid
INNER JOIN RoomCompetitor rc ON rc.competitorid=co.competitorid
WHERE YEAR(occDate)=@year AND MONTH(occdate)=@month AND packageid=@packageID 
AND roomTypeid IN (SELECT roomtypeid FROM CompetitorRoomType WHERE DESCRIPTION=119)

SELECT @Dates = @Dates + '[' + CAST(DATEPART(DAY,DateVal) AS VARCHAR(2)) + '-' + LEFT(DATENAME(MONTH,DateVal),3)+ '],'
FROM #Dates
GROUP BY Dateval

SET @Dates = LEFT(@Dates,LEN(@Dates)-1)

SET @Query = '
SELECT roomtypeid, description, [Name], [HotelName], '+@Dates+'
FROM (  SELECT  HD.roomtypeid, HD.description, HD.[Name], HD.[HotelName], HD.Price, 
                CAST(DATEPART(DAY,DateVal) AS VARCHAR(2)) + ''-'' + LEFT(DATENAME(MONTH,DateVal),3) [Date]
        FROM #Dates D
        LEFT JOIN #HotelData HD
        ON D.DateVal = HD.OccDate) T
PIVOT ( SUM(Price) FOR [Date] IN ('+@Dates+') ) AS PT'

EXEC(@Query)