select a.id,
a.change_id,
LISTAGG(b.name, ',') WITHIN GROUP (ORDER BY b.name) AS "Product Name",
from table_a a,
table_b b
where a.id = 1
and b.change_id = c.change_id
group by a.id, a.change_id
此刻,它正在返回(仅显示一条记录):
1 1 NameA, NameA, NameB, NameC, NameD, Name D
我想返回的是:
1 1 NameA, NameB, NameC, Name D
最佳答案
由于评论中的链接答案没有提供我所喜欢的解决方案,因此无论如何我都会发布它。
我只将table_b与伪数据一起使用以显示概念,您可以轻松添加连接等:
with table_b as ( -- dummy data
select 'name'||mod(level,3) name
,mod(level,3) id
from dual
connect by level < 10
union all
select 'name'||mod(level,2) name
,mod(level,3) id
from dual
connect by level < 10
)
select id
,RTRIM (
XMLAGG (
XMLELEMENT (E,XMLATTRIBUTES (name|| ',' AS "Seg")
)
ORDER BY name ASC
).EXTRACT ('./E[not(@Seg = preceding-sibling::E/@Seg)]/@Seg'),
','
) AS "Product Name"
,LISTAGG(b.name, ',') WITHIN GROUP (ORDER BY b.name) AS "Product Name with dups"
from table_b b
group by id;