简介详情:
我在使用客户端 12c 查询 Oracle SQL Developer 时遇到问题。我已经研究了其他几个关于 SO 的问题,并在谷歌上搜索了这个问题的答案,但最终所有问题的答案都是在 GROUP BY
中包含所有没有聚合函数的列。条款。
我想要的是每年、每周和每天(分别为 PG.CAT
、FD.YEAR
和 FD.WEEK
)为每个类别 (FD.DT
) 获取一个结果。我想对单位、小时数、错误 ( GE.QTY
) 和总小时数求和。我还在两列上执行乘法和除法,并连接最多四个其他表。
查询:
`SELECT
FD.YEAR,
FD.WEEK,
PG.DT,
PG.CAT,
SUM(PG.UNITS) AS UNITS,
SUM(PG.HOURS) AS HOURS,
PM.MTM,
PM.MTM * PG.HOURS AS ADJ_MTM,
(PG.UNITS / (PM.MTM * PG.HOURS)) AS PERC_STANDARD,
SUM(CASE WHEN GE.QTY IS NULL THEN 0 ELSE GE.QTY END) AS QTY,
SUM(WH.TOTALHOURS) AS TOTALHOURS
FROM
PROD_GUNS PG
INNER JOIN PROD_MTM PM
ON PG.CAT = PM.CATEGORY
AND PM.DEPTNO = '018'
AND PG.DT BETWEEN PM.START_DT AND PM.END_DT
INNER JOIN FISCAL_DATES_DAYS FD
ON PG.DT = FD.DT
LEFT OUTER JOIN PROD_GUNS_ERRORS GE
ON PG.EID = GE.EID
AND PG.DT = GE.DT
INNER JOIN WEEKLY_HOURS WH
ON FD.WEEK = WH.DT_WEEK
AND FD.YEAR = WH.DT_YEAR
AND PG.EID = WH.EEXX31
GROUP BY
FD.YEAR,
FD.WEEK,
PG.DT,
PG.CAT,
PM.MTM,
PM.MTM * PG.HOURS,
(PG.UNITS / ( PM.MTM * PG.HOURS))
HAVING
FD.YEAR = '2015'
AND FD.WEEK = '1'
AND PG.DT = '29-DEC-14'
AND PG.CAT = 'Picking'
ORDER BY
PG.DT;`
实际结果:
2015 1 29-DEC-14 Picking 46 0.5 68 34 1.35294117647058823529411764705882352941 0 32.21
2015 1 29-DEC-14 Picking 831 7.72 68 524.96 1.58297775068576653459311185614142029869 0 29.35
预期结果:
2015 1 20-Dec-14 Picking 877 8.22 68 558.96 1.21654501216545 0 61.59
问题:
使用上面的聚合和分组,为什么这不会给我预期的结果?预先感谢大家提供的任何指导。
最佳答案
尝试 SUM/AVG(取决于您的需要)PM.MTM * PG.HOURS AS ADJ_MTM 和 (PG.UNITS/(PM.MTM * PG.HOURS)) AS PERC_STANDARD,而不是按它们分组:
SELECT
FD.YEAR,
FD.WEEK,
PG.DT,
PG.CAT,
SUM(PG.UNITS) AS UNITS,
SUM(PG.HOURS) AS HOURS,
PM.MTM,
SUM(PM.MTM * PG.HOURS )AS ADJ_MTM,
SUM((PG.UNITS / (PM.MTM * PG.HOURS))) AS PERC_STANDARD,
SUM(CASE WHEN GE.QTY IS NULL THEN 0 ELSE GE.QTY END) AS QTY,
SUM(WH.TOTALHOURS) AS TOTALHOURS
FROM
PROD_GUNS PG
INNER JOIN PROD_MTM PM
ON PG.CAT = PM.CATEGORY
AND PM.DEPTNO = '018'
AND PG.DT BETWEEN PM.START_DT AND PM.END_DT
INNER JOIN FISCAL_DATES_DAYS FD
ON PG.DT = FD.DT
LEFT OUTER JOIN PROD_GUNS_ERRORS GE
ON PG.EID = GE.EID
AND PG.DT = GE.DT
INNER JOIN WEEKLY_HOURS WH
ON FD.WEEK = WH.DT_WEEK
AND FD.YEAR = WH.DT_YEAR
AND PG.EID = WH.EEXX31
GROUP BY
FD.YEAR,
FD.WEEK,
PG.DT,
PG.CAT,
PM.MTM
HAVING
FD.YEAR = '2015'
AND FD.WEEK = '1'
AND PG.DT = '29-DEC-14'
AND PG.CAT = 'Picking'
ORDER BY
PG.DT;
关于sql - SQL 分组的结果不符合预期,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30483340/