我有一张 table :t
我的目标:仅提取表中得分最高的“id”,并按week_number 对其进行分组。
询问:
SELECT id,
CAST(EXTRACT(WEEK FROM TIMESTAMP_SECONDS(created_utc)) AS STRING) AS week_number,
MAX(score) AS highest_score
FROM t
WHERE body='r/twinpeaks'
GROUP BY id;
我收到此错误:
错误:SELECT 列表表达式引用了在 [2:49] 处既未分组也未聚合的列 created_utc
我尝试这样做:
SELECT id,
CAST(EXTRACT(WEEK FROM TIMESTAMP_SECONDS(created_utc)) AS STRING) AS week_number,
MAX(score) AS highest_score
FROM t
WHERE body='r/twinpeaks'
GROUP BY week_number, id;
但这就是我得到的:
Row id week_number highest_score
1 dmkb6sv 36 1
2 dn1cd2s 37 2
3 dn43h1k 38 16
4 dn3xf18 38 1
5 dn7i1ko 38 1
6 dnpr9b1 39 1
我要这个:
Row id week_number highest_score
1 dmkb6sv 36 1
2 dn1cd2s 37 2
3 dn43h1k 38 16
6 dnpr9b1 39 1
最佳答案
下面是 BigQuery 标准 SQL
#standardSQL
SELECT
EXTRACT(WEEK FROM TIMESTAMP_SECONDS(created_utc)) AS week_number,
ARRAY_AGG(id ORDER BY score DESC LIMIT 1)[OFFSET(0)] id,
ARRAY_AGG(score ORDER BY score DESC LIMIT 1)[OFFSET(0)] highest_score
FROM `project.dataset.table`
WHERE body = 'r/twinpeaks'
GROUP BY week_number
ORDER BY week_number
关于google-bigquery - 错误 : SELECT list expression references column created_utc which is neither grouped nor aggregated at [2:49],我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49041489/