我有以下 View ,我需要做的是获取具有相同 Vehicle AND OrderCode 的每 2 条记录之间的字段 ActionDate 的日期差异,我如何在 Oracle 数据库中实现这一点。
还要考虑到减去的日期应该是具有 的日期。模式 O - 模式 I
我需要获取差异列表才能获得该时间的平均值。
谢谢你的帮助。
最佳答案
您可以使用分析 LAG() OVER() 函数来获取日期之间的差异。
例如,
SQL> WITH t AS
2 (
3 select 'O' as "MODE", 'V1234567890' as Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 16:34:35','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
4 union all
5 select 'I' as "MODE", 'V1234567890' as Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 15:27:09','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
6 union all
7 select 'O' as "MODE", 'V2987654321' as Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 14:03:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
8 union all
9 select 'I' as "MODE", 'V2987654321' as Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 13:47:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
10 union all
11 select 'O' as "MODE", 'V2987654321' as Vehicle, '1411185798' as OrderCode, to_date('2014-11-20 01:40:58','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
12 union all
13 SELECT 'I' AS "MODE", 'V2987654321' AS Vehicle, '1411185798' AS OrderCode, to_date('2014-11-20 00:47:02','yyyy-mm-dd hh24:mi:ss') AS ActionDate FROM dual
14 )
15 SELECT "MODE",
16 Vehicle,
17 OrderCode,
18 TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
19 TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
20 ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
21 FROM t;
M VEHICLE ORDERCODE DT LAG_DT DIFF
- ----------- ---------- ------------------- ------------------- ----------
I V1234567890 1411196232 2014-11-19 15:27:09
O V1234567890 1411196232 2014-11-19 16:34:35 2014-11-19 15:27:09 .046828704
I V2987654321 1411185798 2014-11-20 00:47:02
O V2987654321 1411185798 2014-11-20 01:40:58 2014-11-20 00:47:02 .037453704
I V2987654321 1411206614 2014-11-20 13:47:02
O V2987654321 1411206614 2014-11-20 14:03:02 2014-11-20 13:47:02 .011111111
6 rows selected.
SQL>
注意: WITH 子句 用于构建 示例数据 ,在您的实际情况下使用您的表,您需要使用 _104567920 _106 _106 _106 _106 _107
SELECT "MODE",
Vehicle,
OrderCode,
TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
FROM your_table;
我把 TO_CHAR 放在了演示目的,你想要的输出是 DIFF 列。关于 MODE ,您可以将其添加到过滤器谓词中。
关于sql - Oracle 中不同行中相同字段的日期/时间差异,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30098289/