json - Powershell:比较对象不比较嵌套对象

Question

或者我是如何不再担心并学会爱上弦乐收藏的

给定以下两个 json 字符串:

$jsonString1 = '{ "baz": "quuz", "cow": [ "moo", "CUD" ], "foo": "bar" }'
$jsonstring2 = '{ "baz": "quuz", "cow": [ "moo", "GRASS" ], "foo": "bar" }'

我想了解它们所代表的对象的差异

<# First attempt: Convert each to an object, then compare normally #>
function Compare-Json {
    <# Make powershell objects from each string #>
    $obj1 = $jsonString1 | ConvertFrom-Json
    $obj2 = $jsonstring2 | ConvertFrom-Json

    Compare-Object $obj1 $obj2
}

PS E:\temp> Compare-Json

PS E:\temp> 

是的，那根本就没有输出。

当前的解决方法是将 json 转换为对象，返回字符串，然后拆分字符串，最后比较每个集合

function Compare-Json {
    <# Convert to pretty json, then split to make a string array #>
    $obj1 = $($jsonString1 | ConvertFrom-Json | ConvertTo-Json) -split ([Environment]::NewLine)
    $obj2 = $($jsonstring2 | ConvertFrom-Json | ConvertTo-Json) -split ([Environment]::NewLine)

    Compare-Object $obj1 $obj2
}


PS E:\temp> Compare-Json

InputObject      SideIndicator                                               
-----------      -------------                                               
"GRASS"          =>                                                          
"CUD"            <=                                                          

PS E:\temp> 

有没有更简单的方法来深度比较两个对象？

Answer 1

不知道是不是更好，但是:

$jsonString1 = '{ "baz": "quuz", "cow": [ "moo", "CUD" ], "foo": "bar" }'
$jsonstring2 = '{ "baz": "quuz", "cow": [ "moo", "GRASS" ], "foo": "bar" }'

compare $jsonString1.split(',:[]{}') $jsonString2.split(',:[]{}')


InputObject                                          SideIndicator                                      
-----------                                          -------------                                      
 "GRASS"                                             =>                                                 
 "CUD"                                               <=