根据这个答案"Android upload video to remote server using HTTP multipart form data"我执行所有步骤。
但我不知道如何为服务器端编码!我的意思是一个 PHP 简单页面,为我最重要的敌人上传服务。
另一个问题是:YOUR_URL(以下代码段的第 3 行)必须是该 PHP 页面的地址吗?
private void uploadVideo(String videoPath) throws ParseException, IOException {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(YOUR_URL);
FileBody filebodyVideo = new FileBody(new File(videoPath));
StringBody title = new StringBody("Filename: " + videoPath);
StringBody description = new StringBody("This is a description of the video");
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("videoFile", filebodyVideo);
reqEntity.addPart("title", title);
reqEntity.addPart("description", description);
httppost.setEntity(reqEntity);
// DEBUG
System.out.println( "executing request " + httppost.getRequestLine( ) );
HttpResponse response = httpclient.execute( httppost );
HttpEntity resEntity = response.getEntity( );
// DEBUG
System.out.println( response.getStatusLine( ) );
if (resEntity != null) {
System.out.println( EntityUtils.toString( resEntity ) );
} // end if
if (resEntity != null) {
resEntity.consumeContent( );
} // end if
httpclient.getConnectionManager( ).shutdown( );
}
最佳答案
这段代码工作正常,我应该使用的 PHP 代码就这么简单:
<?php
$file_path = "uploads/";
$file_path = $file_path . basename( $_FILES['videoFile']['name']);
if(move_uploaded_file($_FILES['videoFile']['tmp_name'], $file_path)) {
echo "success";
} else{
echo "upload_fail_php_file";
}
?>
注意 videoFile 必须完全匹配
reqEntity.addPart("videoFile", filebodyVideo);
您可能面临的最重要问题是服务器配置中post_max_size
和upload_max_filesize
的默认值!默认值太小,当您尝试上传大文件时,PHP 脚本返回:"upload_fail_php_file",没有错误或异常抛出。 所以记住将这些值设置得足够大...
享受编码。
关于php - 安卓 : Upload large files using MultipartEntity,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23504191/