我使用spring security+JSF+primefaces
在自定义登录中，我放了一个命令按钮
但命令按钮没有工作...
当在 p:commandbutton ----------> ajax="false"----------> 工作时!
当在 jsf(core) 中使用 f:ajax 时 --------> 没有工作
我在 spring security.xml 文件中使用:
test.xhtml ----> jsf(core) --------> 没有工作
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html
PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core"
xml:lang="en" lang="en">
<head>
<title>faces-request</title>
</head>
<body>
<h:form>
<center>
<h:outputText id="outtxt" value="#{authentiocationBean.ajaxTest}"/><br/>
<h:inputText id="intxt" value="#{authentiocationBean.ajaxTest}"/><br/>
<h:commandButton value="Submit">
<f:ajax execute="intxt" render="outtxt"/>
</h:commandButton>
</center>
</h:form>
</body>
</html>
Spring_security.xml:
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd">
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/Admin/*" access="hasRole('ROLE_ADMIN')"/>
<intercept-url pattern="/user/*" access="hasAnyRole('ROLE_USER,ROLE_ADMIN')"/>
<form-login login-page="/login.xhtml"
authentication-failure-url="/Fail.xhtml?error"/>
<logout logout-url="/j_spring_security_logout" delete-cookies="JSESSIONID,SPRING_SECURITY_REMEMBER_ME_COOKIE"
invalidate-session="true"
logout-success-url="/login.xhtml"/>
<session-management session-authentication-error-url="/401.xhtml" session-fixation-protection="migrateSession">
<concurrency-control max-sessions="1" expired-url="/login.xhtml"/>
</session-management>
<remember-me key="myAppKey"/>
<access-denied-handler error-page="/AccDe.xhtml"/>
<headers>
<xss-protection/>
<frame-options/>
<cache-control/>
<content-type-options/>
</headers>
<csrf/>
</http>
<authentication-manager alias="authenticationManager">
<authentication-provider>
<jdbc-user-service data-source-ref="myDataSource"
users-by-username-query="select username, password, active from users where username=?"
authorities-by-username-query="select us.username, ur.authority from users us, user_roles ur
where us.user_id = ur.user_id and us.username =? "
/>
<password-encoder ref="passwordEncoder" hash="sha-256"/>
</authentication-provider>
</authentication-manager>
<bean id="passwordEncoder"
xmlns="http://www.springframework.org/schema/beans"
class="org.springframework.security.authentication.encoding.ShaPasswordEncoder">
<!--org.springframework.security.crypto.password.PasswordEncoder for salt!-->
<constructor-arg value="256"/>
</bean>
</beans:beans>
登录页面:
<?xml version='1.0' encoding='UTF-8' ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html"
xmlns:p="http://primefaces.org/ui">
<h:head>
<title>faces-request</title>
</h:head>
<h:body>
<h:form prependId="false" id="formLogin">
<center>
<p:panelGrid style="border-width: 0px;" columns="2">
UserName:
<p:inputText required="true" id="j_username"/>
Password:
<p:password required="true" id="j_password"/>
</p:panelGrid>
<p:commandButton type="submit" id="login" action="#{authentiocationBean.doLogin()}" value="Login"/>
<p:outputLabel for="_spring_security_remember_me" value="Remember me: "/>
<p:selectBooleanCheckbox id="_spring_security_remember_me"/>
<br/>
</center>
</h:form>
</h:body>
</html>
AuthentiocationBean 类
import org.springframework.security.core.Authentication;
import org.springframework.security.core.context.SecurityContextHolder;
import java.io.IOException;
import javax.faces.bean.ManagedBean;
import javax.faces.bean.RequestScoped;
import javax.faces.context.ExternalContext;
import javax.faces.context.FacesContext;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
/**
* @author Admin
*/
@RequestScoped
@ManagedBean
public class AuthentiocationBean {
public String ajaxTest = "Test";
boolean isLogged = false;
public String role = "ROLE_ADMIN";
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
String name = auth.getName();
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String doLogin() throws IOException, ServletException {
isLogged = true;
FacesContext facesContext = FacesContext.getCurrentInstance();
ExternalContext context = facesContext.getExternalContext();
RequestDispatcher dispatcher = ((ServletRequest) context.getRequest()).getRequestDispatcher("/j_spring_security_check");
dispatcher.forward((ServletRequest) context.getRequest(), (ServletResponse) context.getResponse());
FacesContext.getCurrentInstance().responseComplete();
// It's OK to return null here because Faces is just going to exit.
return null;
}
public void doLogout() {
// FacesContext.getCurrentInstance().getExternalContext().invalidateSession();
// return "/logout.xhtml";
// return null;
}
public boolean isLogged() {
return isLogged;
}
public void setLogged(boolean logged) {
isLogged = logged;
}
public String getRole() {
return role;
}
public void setRole(String role) {
this.role = role;
}
public String getAjaxTest() {
return ajaxTest;
}
public void setAjaxTest(String ajaxTest) {
this.ajaxTest = ajaxTest;
}
}
谢谢
最佳答案
它只是一个登录页面，为什么要使用 AJAX 呢？
我已将 Spring 3.1.4 LDAP 支持与 JSF 集成。虽然我最初编写了一个自定义身份验证 bean，但我不再使用它。我不是专家，而且我确信这与我实现的方式不同。
(1) 简单登录页面(摘录):<h:inputText id="j_username"/>
<h:inputText type="password" id="j_password" value=""/>
<h:commandButton name="submit" type="submit" value="Log In" />
<input type="reset" value="Reset" />
(2.1) 在 web.xml 中，我声明了一个上下文参数来命名安全配置文件(在下面的步骤 3 中提到)。
我还声明了 Spring 安全过滤器链，您可以在此处阅读:
http://docs.spring.io/spring-security/site/docs/3.1.4.RELEASE/reference/security-filter-chain.html#filter-chains-with-ns
(2.2) 在faces-config中我声明:<el-resolver>org.springframework.web.jsf.el.SpringBeanFacesELResolver</el-resolver>
(2.3) 在faces-config 中，我声明了一个具有 session 范围的自定义UserSession bean。
UserSession bean 有这个方法:
@PostConstruct
public void loadAuthorities() {
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
. . .
. . .
}
(3) UserSession bean 是从登录页面 (menu.xhtml) 中引用的，该页面在我的安全配置文件中声明(在上面的步骤 2.1 中在 web.xml 中声明):
<security:form-login default-target-url="/menu.xhtml" always-use-default-target="true" authentication-failure-url="/denied.xhtml" />
<security:logout invalidate-session="true" delete-cookies="JSESSIONID" logout-url="/j_spring_security_logout" />
(4) 用户通过身份验证，然后重定向到 menu.xhtml
Menu.xhtml 导致加载 UserSession bean。
UserSession bean 从 SecurityContext 中拉取权限列表。
UserSession bean 提供了简单的包装器来检查用户是否有权查看页面和资源:
public boolean isRole(String role) {
return authorities.contains((String) role);
}
public boolean roleContains(String s);
public boolean roleEndsWith(String s);
. . .
. . .
关于jsf - Spring 安全中的ajax，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23787473/