当我尝试启动 spring web 应用程序时收到以下错误消息:
2012-04-12 13:53:20,491 ERROR [org.springframework.web.servlet.DispatcherServlet] -
Context initialization failed
org.springframework.beans.factory.BeanInitializationException: Could not load properties; nested exception is java.io.FileNotFoundException: class path resource [timex-servlet.properties] cannot be opened because it does not exist
java.io.FileNotFoundException: class path resource [timex-servlet.properties] cannot be opened because it does not exist
at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:137)
at org.springframework.core.io.support.PropertiesLoaderSupport.loadProperties(PropertiesLoaderSupport.java:172)
我正在通过 Eclipse 运行 Tomcat(版本 6.x)。我尝试将 timex-servlet.properties 放入以下目录但无济于事:
WebContent\WEB-INF
WebContent\WEB-INF\classes
WebContent\
这里是timex-servlet.xml中timex-servlet.properties的引用:
<bean id="placeholderConfig"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location"
value="timex-servlet.properties" />
</bean>
有几个 SO 线程处理同一条消息,说要将类路径:放在属性文件引用的前面。所以我尝试了以下方法,但也没有用:
<bean id="placeholderConfig"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location"
value="classpath:timex-servlet.properties" />
</bean>
最佳答案
确保文件放在/WEB-INF/classes
文件夹中并使用classpath:/timex-servlet.properties
(注意classpath后面的斜杠:)
关于spring - java.io.FileNotFoundException : class path resource [timex-servlet. 属性]无法打开,因为它不存在,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10131812/