我真的可以使用一些关于如何将这个 sql 查询带到 NHibernate QueryOver 的指导。我尝试使用 Linq,因为我对 Linq 比较熟悉。我们正在开展的项目正在使用 QueryOver,因此现在最好保持这条路线。
工作 SQL 查询:将 DateTime 舍入为 1 分钟并正确分组/排序/计数...
select dateadd(minute,(datediff(minute,0,dateTimeColumn)/1)*1,0), COUNT(*)
from PartData
group by dateadd(minute,(datediff(minute,0,dateTimeColumn)/1)*1,0)
order by dateadd(minute,(datediff(minute,0,dateTimeColumn)/1)*1,0)
返回预期结果:
2012-08-31 00:00:00.000, 3
2012-08-31 00:01:00.000, 4
2012-08-31 00:02:00.000, 3
2012-08-31 00:03:00.000, 3
2012-08-31 00:04:00.000, 4
2012-08-31 00:05:00.000, 3
2012-08-31 00:06:00.000, 3
2012-08-31 00:07:00.000, 4
2012-08-31 00:08:00.000, 3
编辑
我越来越近了...
private IQueryOver<entities.PartData, entities.PartData> PartPerHourQuery(ISession session)
{
return session.QueryOver<entities.PartData>()
.Select(
Projections.Alias(
Projections.GroupProperty(
Projections.SqlFunction(
new SQLFunctionTemplate(NHibernateUtil.DateTime, "DateAdd(mm,1,Date)"),
NHibernateUtil.DateTime, _partsDate))
, "Date"),
Projections.Alias(Projections.RowCount(), "Count"))
.TransformUsing(Transformers.AliasToBean<entities.PartsPerHour>());
}
产生以下 SQL:
SELECT DateAdd(mm,1,dateTimeColumn), count(*)
FROM [PartData]
GROUP BY DateAdd(mm,1,dateTimeColumn)
只需要弄清楚如何在那里获取 datediff :)
最佳答案
凭借坚持的力量,我成功地赢得了这场战斗。这是我对上述 SQL 查询的 QueryOver ......我相信我已经在这个 NHibernate 事情中转过弯:)
非常感谢任何改进或替代方法来重新产生预期结果的建议。
private IQueryOver<entities.PartData, entities.PartData> PartPerHourQuery(ISession session)
{
return session.QueryOver<entities.PartData>()
.Select(
Projections.Alias(
Projections.GroupProperty(
Projections.SqlFunction(
new SQLFunctionTemplate(NHibernateUtil.DateTime, "DateAdd(minute," +
new SQLFunctionTemplate(
NHibernateUtil.DateTime,
"(DateDiff(minute, 0, Date)/1)*1") +
",0)"),
NHibernateUtil.DateTime, _partsDate))
, "Date"),
Projections.Alias(Projections.RowCount(), "Count"))
.TransformUsing(Transformers.AliasToBean<entities.PartsPerHour>());
}
关于NHibernate 如何将此 SQL 查询转换为 QueryOver 或 Linq,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12230327/