java - HttpGet 与请求正文 android

Question

我尝试通过 HttpGet 在服务器上发出请求。但在消息正文中应该是一个 json 对象。下面的代码不起作用，因为 unit_id 和 sercret_key 没有在正文消息中发送到服务器。我该怎么做？

JSON对象:

{
"unit_id": 12345,
"secret_key": "sdfadfsa6as987654754"
}

我的代码:

private HttpResponse makeRequest(int id, String secretKey) throws Exception {
    BasicHttpParams params = new BasicHttpParams();
    params.setParameter("id", id);

    params.setParameter("secret_key", secretKey);

    httpget.setHeader("Accept", "application/json");

    httpget.setParams(params);
    httpget.setHeader("Content-type", "application/json");

    // Handles what is returned from the page
    return httpclient.execute(httpget);
}

编辑:在 php 中这个请求是这样发出的

<?php
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://0101.apiary.io/api/reservations/");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_HEADER, FALSE);
curl_setopt($ch, CURLOPT_POSTFIELDS, "{\n    \"unit_id\": 12345,\n    \"secret_key\":     \"sdfadfsa6as987654754\"\n}");
curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: application/json"));
$response = curl_exec($ch);
curl_close($ch);

var_dump($response);

Answer 1

基本上，您不能使用 HTTP/GET 请求在正文(JSON 或任何内容)中发送行数据。 协议(protocol)根本不允许您这样做。显然，您也必须使用 POST 在 Android 中执行此操作。 :)

更新

我错了。事实上，该协议(protocol)确实允许您将一个实体放入请求对象中。可以使用此类代替 Apache HttpGet。

public class HttpGetWithEntity extends HttpEntityEnclosingRequestBase {

    public HttpGetWithEntity() {
        super();
    }

    public HttpGetWithEntity(URI uri) {
        super();
        setURI(uri);
    }

    public HttpGetWithEntity(String uri) {
        super();
        setURI(URI.create(uri));
    }

    @Override
    public String getMethod() {
        return HttpGet.METHOD_NAME;
    }
}

然后像下面这样使用它，

HttpClient client = new DefaultHttpClient();
HttpGetWithEntity myGet = new HttpGetWithEntity("Url here");
myGet.setEntity(new StringEntity("This is the body", "UTF8"));
HttpResponse response = client.execute(myGet);

找到HttpGetWithEntity 的源here