我有一个扩展 ArrayAdapter 的类。我无法将 ListAdapter 设置为我的 ListView，因为我不知道在尝试创建 ListAdapter 时代码应该是什么。这是我当前的代码。
class Item {
String username;
String number;
String content;
}
class ListAdapter extends ArrayAdapter<Item> {
public ListAdapter(Context context, int textViewResourceId) {
super(context, textViewResourceId);
// TODO Auto-generated constructor stub
}
private List<Item> items;
public ListAdapter(Context context, int resource, List<Item> items) {
super(context, resource, items);
this.items = items;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View v = convertView;
if (v == null) {
LayoutInflater vi;
vi = LayoutInflater.from(getContext());
v = vi.inflate(R.layout.list_item, null);
}
Item p = items.get(position);
if (p != null) {
TextView tt = (TextView) v.findViewById(R.id.id);
TextView tt1 = (TextView) v.findViewById(R.id.categoryId);
TextView tt3 = (TextView) v.findViewById(R.id.description);
if (tt != null) {
tt.setText(p.getId());
}
if (tt1 != null) {
tt1.setText(p.getCategory().getId());
}
if (tt3 != null) {
tt3.setText(p.getDescription());
}
}
return v;
}
}
这是我遇到问题的地方，试图声明 ListAdapter
List <Item> tempList = new ArrayList <Item>();
ListView yourListView = (ListView) findViewById(android.R.id.list);
// Here is the problem
ListAdapter customAdapter = new ListAdapter(this, R.layout.list_item, List<tempList> //the error occurs right here);
yourListView .setAdapter(customAdapter);
最佳答案
改变
ListAdapter customAdapter = new ListAdapter(this, R.layout.list_item,List<tempList>)
到
ListAdapter customAdapter = new ListAdapter(this, R.layout.list_item, tempList);
//...........
删除列表只添加tempList
关于android - 如何将 ArrayAdapter 设置为 Listview - Android，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18372450/