我的数据库中有 3 个表,
图片如下,我已关注 http://www.yiiframework.com/wiki/281/searching-and-sorting-by-related-model-in-cgridview/
获得具有搜索和排序目的的最终网格。所以我在 search()
中连接了 2 个表功能如
public function search() { // Warning: Please modify the following code to remove attributes that // should not be searched. $criteria=new CDbCriteria; $criteria->with = array( 'bposite' ); $criteria->together = false; $criteria->with = array( 'client' ); $criteria->compare('id',$this->id); // $criteria->compare('client_id',$this->client_id); // $criteria->compare('bposite_id',$this->bposite_id); $criteria->compare('userid',$this->userid,true); $criteria->compare('password',$this->password,true); $criteria->compare( 'bposite.name', $this->bposite_search, true ); $criteria->compare( 'client.name', $this->client_search, true ); return new CActiveDataProvider($this, array( 'criteria'=>$criteria, 'sort'=>array( 'attributes'=>array( 'client_search'=>array( 'asc'=>'client.name', 'desc'=>'client.name DESC', ), 'bposite_search'=>array( 'asc'=>'bposite.name', 'desc'=>'bposite.name DESC', ), '*', ), ), )); } }
但是我得到了客户的结果,bposite 搜索和排序显示了类似的问题
> Error 500: <h1>CDbException</h1>
> <p>CDbCommand failed to execute the SQL statement: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'bposite.name'
> in 'where clause'. The SQL statement executed was: SELECT
> COUNT(DISTINCT `t`.`id`) FROM `clientbposites` `t` LEFT OUTER JOIN
> `client` `client` ON (`t`.`client_id`=`client`.`id`) WHERE
> (bposite.name LIKE :ycp0)
> (D:\wamp\www\yi\framework\db\CDbCommand.php:516)</p><pre>#0
> D:\wamp\www\yi\framework\db\CDbCommand.php(411):
> CDbCommand->queryInternal('fetchColumn', 0, Array)
how can implement non-related table with cgridview search and sort options.
最佳答案
我已经写了一篇关于这个的分步博客文章。如果您遇到困难,请随意阅读并提出问题。不要在这里写下所有内容来重复自己,这是链接:http://www.mrsoundless.com/post/2011/05/09/Searching-and-sorting-a-column-from-a-related-table-in-a-CGridView.aspx
它似乎帮助了很多人。希望它也能帮助你:)
关于Yii CGridView 使用关系表排序和搜索,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10725520/