我正在创建基于 react native 的电子商务应用程序。这里我需要从 url shared 打开单个产品页面。实际上,当应用程序处于终止状态时它会工作,但如果应用程序处于后台/非 Activity 状态,它将不会工作。在后台/非 Activity 状态下打开时共享 url 变为空。我附上了我的代码。
// following code working for app killing state
componentWillMount() {
if (Platform.OS === 'android') {
console.log("Testing");debugger
//Constants.OneTimeFlag == false;
Linking.getInitialURL().then(url => {
console.log(url);
var str = url
var name = str.split('/')[4]
Constants.isLinking = true;
this.setState({ shop_Id: name})
if (str)
{
this.setState({ isFromHomeLinking:'FROM_LINK' })
this.props.navigation.navigate('SingleProductScreen', { ListViewClickItemHolder: [this.state.shop_Id,1,this.state.isFromHomeLinking] });
}
});
}
else {
Linking.addEventListener('url', this.handleNavigation);
}
}
Not working code following..
componentDidMount() {
AppState.addEventListener('change', this._handleAppStateChange);
}
componentWillUnmount() {
AppState.removeEventListener('change', this._handleAppStateChange);
}
this.state.appState declared in constructor(props)
_handleAppStateChange = (nextAppState) => {
if (this.state.appState.match(/inactive|background/) && nextAppState === 'active') {
console.log('App has come to the foreground!');debugger
if (Platform.OS === 'android') {
console.log("Testing");debugger
//Constants.OneTimeFlag == false;
Linking.getInitialURL().then(url => {
console.log(url);
var str = url
var name = str.split('/')[4]
Constants.isLinking = true;
this.setState({ shop_Id: name})
if (str)
{
this.setState({ isFromHomeLinking:'FROM_LINK' })
this.props.navigation.navigate('SingleProductScreen', { ListViewClickItemHolder: [this.state.shop_Id,1,this.state.isFromHomeLinking] });
}
});
}
else {
Linking.addEventListener('url', this.handleNavigation);
}
}
}
当我在后台状态 Linking.getInitialURL() 中打开来自 whatsapp 和应用程序的外部链接时,接收为 null ..
以下是 list 文件
<activity
android:name=".MainActivity"
android:label="@string/app_name"
android:configChanges="keyboard|keyboardHidden|orientation|screenSize"
android:windowSoftInputMode="adjustResize"
android:launchMode="singleTask">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http"
android:host="demo1.zgroo.com" />
</intent-filter>
</activity>
以下是我的示例 URL..
请让我知道任何解决方案..
提前致谢..
最佳答案
您需要为此案例注册 Linking 监听器。
componentDidMount() {
Linking.addEventListener('url', this._handleOpenURL);
},
componentWillUnmount() {
Linking.removeEventListener('url', this._handleOpenURL);
},
_handleOpenURL(event) {
console.log(event.url);
}
关于android - 当应用程序处于后台状态 React native 时深度链接不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53256246/