我正在使用处理程序重复提示用户输入,例如5分钟。当设备进入休眠模式并且屏幕被锁定时,如何在我的应用提示用户输入时唤醒设备?我试过这个但它似乎不起作用。我在 list 中添加了WAKE_LOCK
权限。
class BtHandler extends Handler {
private PowerManager pm;
private WakeLock wl;
@Override
public void handleMessage(Message msg) {
pm = (PowerManager)FixedNode.this.getSystemService(Context.POWER_SERVICE);
if (!pm.isScreenOn()) {
wl = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK, "TAG");
wl.acquire();
}
FixedNode.this.setAlwaysDiscoverable();
wl.release();
}
}
有什么想法吗?
编辑:使用 AlarmManager
广播自定义 Intent 。
mReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
Vibrator v = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
v.vibrate(300);
PowerManager pm = (PowerManager) getSystemService(Context.POWER_SERVICE);
KeyguardManager km = (KeyguardManager) getSystemService(Context.KEYGUARD_SERVICE);
WakeLock wl = null;
if (!pm.isScreenOn()) {
KeyguardLock kl = km.newKeyguardLock("TAG");
kl.disableKeyguard();
wl = pm.newWakeLock(
PowerManager.SCREEN_BRIGHT_WAKE_LOCK |
PowerManager.ACQUIRE_CAUSES_WAKEUP, "TAG");
wl.acquire();
}
Toast.makeText(context, "Alarm worked", Toast.LENGTH_LONG).show();
wl.release();
}
};
mFilter = new IntentFilter(ACTION_NAME);
Intent mIntent = new Intent(ACTION_NAME);
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, mIntent, 0);
AlarmManager am = (AlarmManager) getSystemService(ALARM_SERVICE);
am.set(AlarmManager.RTC_WAKEUP, System.currentTimeMillis() + (120 * 1000), pendingIntent);
Toast.makeText(this, "Alarm set", Toast.LENGTH_LONG).show();
最佳答案
通常 wakelock
不会实际打开屏幕。所以你应该用
ACQUIRE_CAUSES_WAKEUP
作为附加标志。
关于android - 当应用程序提示用户时唤醒设备,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6445844/