我正在尝试使用 seqdef
创建一个序列对象使用 SPELL 格式。这是我的数据示例:
spell <- structure(list(ID = c(1, 3, 3, 4, 5, 5, 6, 8, 9, 10, 11, 11,
12, 13, 13, 13, 13, 14, 14, 14, 14, 14, 14, 14, 14, 14, 15, 15,
15, 15, 15, 15, 15, 16, 16, 16, 16, 17, 17, 17, 18, 18, 18, 19,
19), status = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 2, 3, 1, 2, 3, 2, 3, 1, 1, 1, 3, 1, 3, 3, 1, 3, 1, 1, 1,
1, 1, 3, 3, 1, 3, 1, 1, 1), time1 = c(1, 1, 57, 1, 1, 91, 1,
1, 1, 1, 1, 104, 1, 1, 60, 109, 121, 1, 42, 47, 54, 64, 72, 78,
85, 116, 1, 29, 39, 69, 74, 78, 88, 1, 16, 40, 68, 1, 30, 123,
1, 39, 51, 1, 61), time2 = c(125, 57, 125, 125, 91, 125, 125,
125, 125, 125, 104, 125, 125, 60, 109, 121, 125, 42, 47, 54,
64, 72, 78, 85, 116, 125, 29, 39, 69, 74, 78, 88, 125, 16, 40,
68, 125, 30, 123, 125, 39, 51, 125, 61, 125)), .Names = c("ID",
"status", "time1", "time2"), row.names = c(NA, 45L), class = "data.frame")
当我尝试定义序列对象时,抛出了一个奇怪的错误:
spell.seq <- seqdef(data=spell, informat="SPELL", id="ID", begin="time1", end="time2",
status="status", limit=125,process=FALSE)
[>] time axis: 1 -> 125
[>] SPELL data converted into 17 STS sequences
[>] 3 distinct states appear in the data:
1 = 1
2 = 2
3 = 3
[>] state coding:
[alphabet] [label] [long label]
1 1 1 1
2 2 2 2
3 3 3 3
[>] 17 sequences in the data set
[>] min/max sequence length: 125/125
Error in `row.names<-.data.frame`(`*tmp*`, value = value) :
invalid 'row.names' length
但是,如果我通过
seqformat
间接地做同样的事情,保留相同的参数,不会抛出错误:sts <- seqformat(data=spell,from="SPELL",to="STS",
id="ID",begin="time1",end="time2",status="status",
limit=125,process=FALSE)
seqs <- seqdef(sts,right="DEL")
使用 TraMineR 1.8-5 和 R 3.0.0 Windows 7 64 位。这是一个错误还是我做错了什么?提前致谢。
最佳答案
快速浏览 seqdef()
的来源为如何row.names
are set 显示它们是根据 id
的值设置的争论。
在看 ?seqdef
为 id
显示
id
optional argument for setting the rownames of the sequence object. If NULL (default), the rownames are taken from the input data. If set to "auto", sequences are numbered from 1 to the number of sequences. A vector of rownames of length equal to the number of sequences may be specified as well.
从您传递的问题中的示例
id="ID"
不符合这些标准。将此更改为 id=NULL
允许命令按预期完成并使用 identical( spell.seq, seqs)
检查相等性 yield true
.
关于r - 从 SPELL 数据创建序列对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16110508/