使用 plotly
我想让每个表面都有不同的颜色。
library(plotly)
t1 <- seq(-3, 3, 0.1); t2 <- seq(-3, 3, 0.1)
p1 <- matrix(nrow = length(t1), ncol = length(t2))
p2 <- matrix(nrow = length(t1), ncol = length(t2))
p8a1 <- 1.2
p8a2 <- 1
p8d <- -1
p8b1 <- 0.7
p8b2 <- 0.6
for (i in 1:length(t2)) {
for (j in 1:length(t1)) {
p1[i, j] <- 1 / (1 + exp(-1.7 * (p8a1 * t1[j] + p8a2 * t2[i] + p8d)))
p2[i, j] <- (1 / (1 + exp(-1.7 * p8a1 * (t1[j]- p8b1)))) *
(1 / (1 + exp(-1.7 * p8a2 * (t2[j]- p8b2))))
}
}
df1 <- list(t1, t2, p1)
df2 <- list(t1, t2, p2)
names(df1) <- c("t1", "t2", "p1")
names(df2) <- c("t1", "t2", "p2")
m <- list(l = 10, r = 10, b = 5, t = 0, pad = 3)
p <- plot_ly(color = c("red", "blue")) %>%
add_surface(x = df1$t1,
y = df1$t2,
z = df1$p1,
opacity = 0.8) %>%
add_surface(x = df2$t1,
y = df2$t2,
z = df2$p2,
opacity = 1) %>%
layout(autosize = F, width = 550, height = 550, margin = m,
scene = list(xaxis = list(title = "Theta 1"),
yaxis = list(title = "Theta 2"),
zaxis = list(title = "P")),
dragmode = "turntable")
p
不幸的是,我无法更改这两个表面的颜色。我尝试添加
color = I("red")
和 color = I("blue")
参数转换为 add_surface
但这只是将两个表面的色阶从红色变为蓝色。我也尝试添加
color = "red"
进入 plot_ly()
并添加 inherit = F
进入第二 add_surface
.这仅将第一个表面更改为红色,但仅将黄色默认颜色更改为红色。我希望有一个表面红色和第二个蓝色。
最佳答案
听起来微不足道,但在 Plotly 中有点棘手。曲面图的颜色要么来自 z 值,要么来自与 z 具有相同维度的数组。这个颜色数组只接受数值,不接受颜色字符串或 RGB 值。
所以让我们为我们的颜色定义一个数组
color <- rep(0, length(df1$p1))
dim(color) <- dim(df1$p1)
接下来我们需要欺骗 Plotly 忽略色阶。
surfacecolor=color,
cauto=F,
cmax=1,
cmin=0
等等,我们有一个均匀着色的 plotly 。
library(plotly)
t1 <- seq(-3, 3, 0.1); t2 <- seq(-3, 3, 0.1)
p1 <- matrix(nrow = length(t1), ncol = length(t2))
p2 <- matrix(nrow = length(t1), ncol = length(t2))
p8a1 <- 1.2
p8a2 <- 1
p8d <- -1
p8b1 <- 0.7
p8b2 <- 0.6
for (i in 1:length(t2)) {
for (j in 1:length(t1)) {
p1[i, j] <- 1 / (1 + exp(-1.7 * (p8a1 * t1[j] + p8a2 * t2[i] + p8d)))
p2[i, j] <- (1 / (1 + exp(-1.7 * p8a1 * (t1[j]- p8b1)))) *
(1 / (1 + exp(-1.7 * p8a2 * (t2[j]- p8b2))))
}
}
df1 <- list(t1, t2, p1)
df2 <- list(t1, t2, p2)
names(df1) <- c("t1", "t2", "p1")
names(df2) <- c("t1", "t2", "p2")
m <- list(l = 10, r = 10, b = 5, t = 0, pad = 3)
color <- rep(0, length(df1$p1))
dim(color) <- dim(df1$p1)
p <- plot_ly(colors = c('red', 'blue')) %>%
add_surface(x = df1$t1,
y = df1$t2,
z = df1$p1,
opacity = 0.8,
#surfacecolor=c('red')
surfacecolor=color,
cauto=F,
cmax=1,
cmin=0
)
color2 <- rep(1, length(df2$p2))
dim(color2) <- dim(df2$p2 )
p <- add_surface(p,
x = df2$t1,
y = df2$t2,
z = df2$p2,
opacity = 1,
surfacecolor=color2,
cauto=F,
cmax=1,
cmin=0)
p
关于r - plotly - 不同表面的不同颜色,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46150158/