java - 是否可以忽略异常？

Question

在 Java 中，是否可以使具有 throws 语句的方法不被检查。

例如:

public class TestClass {
    public static void throwAnException() throws Exception {
        throw new Exception();
    }
    public static void makeNullPointer() {
        Object o = null;
        o.equals(0);//NullPointerException
    }
    public static void exceptionTest() {
        makeNullPointer(); //The compiler allows me not to check this
        throwAnException(); //I'm forced to handle the exception, but I don't want to
    }
}

Answer 1

你可以尝试什么也不做:

public static void exceptionTest() {
    makeNullPointer(); //The compiler allows me not to check this
    try {
        throwAnException(); //I'm forced to handle the exception, but I don't want to
    } catch (Exception e) { /* do nothing */ }
}

请记住，在现实生活中这是非常不明智的。这可以隐藏一个错误，让你整整一周都在寻找狗，而问题实际上是一只猫(ch)。 _{^{(来吧，至少放一个 System.err.println() - 在这里记录是最好的做法，正如@BaileyS 所建议的那样。)}}

Unchecked exceptions in Java扩展 RuntimeException 类。 throw 它们不会要求客户提供 catch:

// notice there's no "throws RuntimeException" at the signature of this method
public static void someMethodThatThrowsRuntimeException() /* no need for throws here */ {
    throw new RuntimeException();
}

扩展 RuntimeException 的类也不需要 throws 声明。

还有 a word from Oracle关于它:

Here's the bottom line guideline: If a client can reasonably be expected to recover from an exception, make it a checked exception. If a client cannot do anything to recover from the exception, make it an unchecked exception.