ruby-on-rails - rails 路由显示操作嵌套资源

Question

是的，问题是，我创建了一个这样的嵌套资源:

resources :albums do 
  resources :elements
end

并且 rake routes 命令显示:

album_element GET /albums/:album_id/elements/:id(.:format) elements#show

所以当我在
.../专辑/1
我可以去
.../专辑/1/元素

这将启动元素 Controller 的索引操作，就好了。
但是如果我将 index.html.erb 编辑为

<%= link_to 'Show', album_element_path %>

我收到这样的错误:

Started GET "/albums/1/elements" for 176.221.47.67 at Tue Oct 09 14:25:39 +0200 2012
Processing by ElementsController#index as HTML
Parameters: {"album_id"=>"1"}
Rendered elements/index.html.erb within layouts/application (9.2ms)
Completed 500 Internal Server Error in 123ms

ActionController::RoutingError (No route matches {:controller=>"elements", :action=>"show"}):
app/views/elements/index.html.erb:29:in `_app_views_elements_index_html_erb___13604879__168097178'
app/views/elements/index.html.erb:18:in `each'
app/views/elements/index.html.erb:18:in `_app_views_elements_index_html_erb___13604879__168097178'
app/controllers/elements_controller.rb:7:in `index'

所以它说没有路线匹配......但我实际上在我的 rake route 显示了？
我究竟做错了什么 ？

Answer 1

您需要为专辑元素路径提供两个必要的参数:

<%= link_to 'Show', album_element_path(@album, @element) %>