根据 VB6 的 MSDN 帮助
Floating-point values can be expressed as mmmEeee or mmmDeee, in which mmm is the mantissa and eee is the exponent (a power of 10). The highest positive value of a Single data type is 3.402823E+38, or 3.4 times 10 to the 38th power; the highest positive value of a Double data type is 1.79769313486232D+308, or about 1.8 times 10 to the 308th power. Using D to separate the mantissa and exponent in a numeric literal causes the value to be treated as a Double data type. Likewise, using E in the same fashion treats the value as a Single data type.
现在在 VB6 IDE 中我试图输入这个
const MAX_DOUBLE as Double = 1.79769313486232D+308
但是，一旦我离开那条线，IDE 就会抛出错误 6(溢出)
An overflow results when you try to make an assignment that exceeds the limitations of the target of the assignment. ...
那么如何定义 MAX_DOUBLE(和 MIN_DOUBLE)？
最佳答案
编辑:
解决了!
Const test As Double = 1.79769313486231E+308 + 5.88768018655736E+293
仔细检查它到二进制级别，应该尽可能高。您可以继续添加 1 等值，但它会产生一个等于而不是大于的数字。
输出是这样的:
01111111|11101111|11111111|11111111|11111111|11111111|11111111|11111111
这确实是 DoubleMax
老的:
您可以使用 Positive infinity .
关于ide - 如何在 VB6 中声明 MAX_DOUBLE？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/929069/