awk - 使用 awk (gawk) 进行数字排序

Question

试图解决一个 question ，我写了以下gnu-awk脚本并遇到排序问题( 应该 已阅读手册)。

从手册:

Because IGNORECASE affects string comparisons, the value of IGNORECASE also affects sorting for both asort() and asorti(). Note also that the locale's sorting order does not come into play; comparisons are based on character values only.

这是建议的解决方案:

awk '{
    lines[$0]=length($0)
}
END {
    for(line in lines) { tmp[lines[line],line] = line }
    n = asorti(tmp)
    for(i=1; i<=n; i++) {
        split(tmp[i], tmp2, SUBSEP); 
        ind[++j] = tmp2[2]
    }
    for(i=n; i>0; i--)
        print ind[i],lines[ind[i]]
}' file
aaaaa foo 9
aaa foooo 9
aaaa foo 8
aaa foo 7
as foo 6
a foo 5
aaaaaaa foooo 13

我尝试添加 0 以强制数字类型，但是无法达到所需的输出。有没有办法在 awk/gawk 中模拟数字排序？ ?

输入文件:

aaa foooo
aaaaaaa foooo
a foo
aaa foo
aaaaa foo
as foo
aaaa foo

期望输出:

aaaaaaa foooo
aaaaa foo     # Doesnt matter which one comes first (since both are same size)
aaa foooo     # Doesnt matter which one comes first (since both are same size)
aaaa foo
aaa foo
as foo
a foo

脚本输出中显示的数字仅用于说明如何进行排序。

Answer 1

看这个例子，Jaypal，你会得到:

kent$  cat f
3333333
50
100
25
44

kent$  awk '{a[$0]}END{asorti(a,b);for(i=1;i<=NR;i++)print b[i]}' f          
100
25
3333333
44
50

kent$  awk '{a[$0]}END{asorti(a,b,"@val_num_asc");for(i=1;i<=NR;i++)print b[i]}' f
25
44
50
100
3333333