jpa - 在 WHERE 中使用 "CASE WHEN"语句进行查询会导致 QuerySyntaxException : unexpected AST

Question

我正在尝试使用 Spring Data 进行查询，但无法使其工作:

@Query(SELECT t FROM Thing t WHERE name LIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >= :maxVal) END)
Page<Thing> getThings(@Param("name") String name, @Param("maxVal") int maxVal, @Param("minVal") minVal); 

堆栈跟踪:

Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: CASE near line 1, column 49 [SELECT t FROM Thing t WHERE name LIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >= :maxVal) END] at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1683) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:331) at sun.reflect.GeneratedMethodAccessor40.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:606) at org.springframework.orm.jpa.ExtendedEntityManagerCreator$ExtendedEntityManagerInvocationHandler.invoke(ExtendedEntityManagerCreator.java:334) at com.sun.proxy.$Proxy83.createQuery(Unknown Source) at org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:78) ... 207 more

Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: CASE near line 1, column 49 [SELECT t FROM Thing t WHERE name LIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >= :maxVal) END] at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91) at org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109) at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:284) at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:206) at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158) at org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:126) at org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:88) at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:190) at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301) at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236) at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1800) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:328)

我使用它是因为我想至少使用五个过滤器进行更长的查询，并且我想简化进行不同查询的过滤器组合的工作。

不知道是否有不同(更好)的方式来做我想做的事，如果是的话，很高兴听到。

谢谢你。

编辑:使用 native 查询工作正常，但与分页不兼容......

Answer 1

看起来 Hibernate 在直接返回 bool 文字时无法评估 CASE 表达式的结果。解决方法是使 CASE 表达式成为另一个表达式的一部分，例如通过将它与另一个 bool 文字进行比较。

所以而不是:

... AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END

尝试:

... AND (CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END) = TRUE

但是看看那个表达式，这样做会不会更简单:

... AND (:minVal <= 0 OR val <= :minVal)

不是等价的吗？