json - Jersey 2.8客户端在反序列化期间不会忽略未知属性

标签 json jackson jersey-2.0 jersey-client

我正在使用Jersey Client 2.8并尝试注册自己的Jackson配置器,该配置器将设置自定义ObjectMapper属性。

public class ConnectionFactory {
   private final Client client;
   public ConnectionFactory() {
   ClientConfig clientConfig = new ClientConfig();
   clientConfig.property(ClientProperties.FOLLOW_REDIRECTS, true);
   clientConfig.property(ClientProperties.CONNECT_TIMEOUT, connTimeoutSec * 1000);
   clientConfig.property(ClientProperties.READ_TIMEOUT, readTimeoutSec * 1000);
   this.client = ClientBuilder.newBuilder().register(JacksonConfigurator.class).register(JacksonFeature.class).withConfig(clientConfig).build();
   // Some more code here ...
   }
}

根据Jackson Registration文档中的示例8.15,这应将以下JacksonConfigurator类注册到客户端。
import javax.ws.rs.ext.ContextResolver;
import javax.ws.rs.ext.Provider;

import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.databind.ObjectMapper;

/**
 * Provides custom configuration for jackson.
 */
@Provider
public class JacksonConfigurator implements ContextResolver<ObjectMapper> {

    private final ObjectMapper mapper;

    public JacksonConfigurator() {
        mapper = new ObjectMapper();
        mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
    }

    @Override
    public ObjectMapper getContext(Class<?> type) {
        return mapper;
    }

}

如果我反序列化来自客户端的响应,则客户端应忽略响应中无法识别的字段。但我收到以下错误-
Caused by: com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "xyz" (class LookupData), not marked as ignorable (3 known properties: "abc", "pqr", "def"])
 at [Source: org.glassfish.jersey.message.internal.EntityInputStream@55958273; line: 1, column: 11] (through reference chain: LookupData["xyz"])
    at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:51)
    at com.fasterxml.jackson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:731)
    at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:915)
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1292)
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1270)
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:247)
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:118)
    at com.fasterxml.jackson.databind.ObjectReader._bind(ObjectReader.java:1232)
    at com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:676)
    at com.fasterxml.jackson.jaxrs.base.ProviderBase.readFrom(ProviderBase.java:800)
    at org.glassfish.jersey.message.internal.ReaderInterceptorExecutor$TerminalReaderInterceptor.invokeReadFrom(ReaderInterceptorExecutor.java:257)
    at org.glassfish.jersey.message.internal.ReaderInterceptorExecutor$TerminalReaderInterceptor.aroundReadFrom(ReaderInterceptorExecutor.java:229)
    at org.glassfish.jersey.message.internal.ReaderInterceptorExecutor.proceed(ReaderInterceptorExecutor.java:149)
    at org.glassfish.jersey.message.internal.MessageBodyFactory.readFrom(MessageBodyFactory.java:1124)
    at org.glassfish.jersey.message.internal.InboundMessageContext.readEntity(InboundMessageContext.java:851)
    ... 39 more

有人可以在注册JacksonConfigurator类时让我知道是否遗漏了什么吗?

最佳答案

尝试使用已正确配置的JacksonJsonProvider初始化Jersey客户端:

final JacksonJsonProvider jacksonJsonProvider = new JacksonJaxbJsonProvider().configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
final Client client = ClientBuilder.newClient(new ClientConfig(jacksonJsonProvider));

jackson 2.5.1和 Jersey 2.17对此进行了测试

关于json - Jersey 2.8客户端在反序列化期间不会忽略未知属性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26393310/

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