我很难将此查询(直接在数据库上工作)表示为 Hibernate(3.2.5 版)中的条件查询:
SELECT s.*
FROM ftp_status s
WHERE (s.datetime,s.connectionid) IN (SELECT MAX(f.datetime),
f.connectionid
FROM ftp_status f
GROUP BY f.connectionid);
到目前为止,这是我想出的不起作用的方法,并抛出了
could not resolve property: datetime of: common.entity.FtpStatus
错误信息:Criteria crit = s.createCriteria(FtpStatus.class);
crit = crit.createAlias("connections", "c");
crit = crit.createAlias("id", "f");
ProjectionList proj = Projections.projectionList();
proj = proj.add(Projections.max("f.datetime"));
proj = proj.add(Projections.groupProperty("c.connectionid"));
crit = crit.setProjection(proj);
List<FtpStatus> dtlList = crit.list();
下面是Netbeans 6.8直接从数据库生成的相关引用配置:
FtpStatus.hbm.xml -
<hibernate-mapping>
<class name="common.entity.FtpStatus" table="ftp_status" catalog="common">
<composite-id name="id" class="common.entity.FtpStatusId">
<key-property name="siteid" type="int">
<column name="siteid" />
</key-property>
<key-property name="connectionid" type="int">
<column name="connectionid" />
</key-property>
<key-property name="datetime" type="timestamp">
<column name="datetime" length="19" />
</key-property>
</composite-id>
<many-to-one name="connections" class="common.entity.Connections" update="false" insert="false" fetch="select">
<column name="connectionid" not-null="true" />
</many-to-one>
<many-to-one name="sites" class="common.entity.Sites" update="false" insert="false" fetch="select">
<column name="siteid" not-null="true" />
</many-to-one>
<property name="upInd" type="boolean">
<column name="up_ind" not-null="true" />
</property>
<property name="lastMessage" type="string">
<column name="last_message" length="65535" not-null="true" />
</property>
</class>
</hibernate-mapping>
Connections.hbm.xml -
<hibernate-mapping>
<class name="common.entity.Connections" table="connections" catalog="common">
<id name="connectionid" type="java.lang.Integer">
<column name="connectionid" />
<generator class="identity" />
</id>
<property name="ip" type="string">
<column name="ip" length="15" not-null="true" />
</property>
<property name="port" type="int">
<column name="port" not-null="true" />
</property>
<property name="user" type="string">
<column name="user" length="8" not-null="true" />
</property>
<property name="password" type="string">
<column name="password" length="50" not-null="true" />
</property>
<set name="ftpStatuses" inverse="true">
<key>
<column name="connectionid" not-null="true" />
</key>
<one-to-many class="common.entity.FtpStatus" />
</set>
</class>
</hibernate-mapping>
我知道我遗漏了一些东西,但是我在 hibernate 上的谷歌搜索还没有发现它。或者直接使用
s.createSQLQuery()
进行 SQL 查询或 s.createQuery()
也是可以接受的,但我写那个的成功更少......
最佳答案
Criteria
您提供的似乎只生成内部查询部分。您可以组合内部查询,例如通过使用 DetachedCriteria
:
DetachedCriteria maxDateQuery = DetachedCriteria.forClass(FtpStatus.class);
ProjectionList proj = Projections.projectionList();
proj.add(Projections.max("datetime"));
proj.add(Projections.groupProperty("connectionid"));
maxDateQuery.setProjection(proj);
Criteria crit = s.createCriteria(FtpStatus.class);
crit.add(Subqueries.propertiesEq(new String[] {"datetime", "connectionid"}, maxDateQuery));
List<FtpStatus> dtlList = crit.list();
请注意,直到 Hibernate 4.0.0.CR5 (HHH-6766) 才实现对多列子查询的支持。 .
至于原生 SQL 查询,Hibernate 的
createSQLString
如果希望在结果查询中具有显式列名,则应该立即使用您指定的查询字符串或添加的查询中涉及的实体。String queryString = "SELECT {status.*}"
+ " FROM ftp_status status"
+ " WHERE (datetime, connectionid) IN ("
+ " SELECT MAX(datetime), connectionid"
+ " FROM ftp_status"
+ " GROUP BY connectionid"
+ " )";
SQLQuery query = s.createSQLQuery(queryString).addEntity("status", FtpStatus.class);
List<FtpStatus> dtlList = query.list();
关于使用 Max() 投影对键字段和按外主键分组的 Hibernate 条件查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2723803/