我有两个 list :
listA:
[[Name: mr good, note: good,rating:9], [Name: mr bad, note: bad, rating:5]]
listB:
[[Name: mr good, note: good,score:77], [Name: mr bad, note: bad, score:12]]
我想得到这个
listC:
[[Name: mr good, note: good,, rating:9, score:77], [Name: mr bad, note: bad, rating:5,score:12]]
我怎么办?
谢谢。
最佳答案
收集listA中的所有元素,并在listB中找到等价的elementA。从 listB 中删除它,并返回组合元素。
如果我们说你的结构是上面的,我可能会这样做:
def listC = listA.collect( { elementA ->
elementB = listB.find { it.Name == elementA.Name }
// Remove matched element from listB
listB.remove(elementB)
// if elementB == null, I use safe reference and elvis-operator
// This map is the next element in the collect
[
Name: it.Name,
note: "${it.note} ${elementB?.note :? ''}", // Perhaps combine the two notes?
rating: it.rating?:0 + elementB?.rating ?: 0, // Perhaps add the ratings?
score: it.score?:0 + elementB?.score ?: 0 // Perhaps add the scores?
] // Combine elementA + elementB anyway you like
}
// Take unmatched elements in listB and add them to listC
listC += listB
关于list - Groovy 合并两个列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2598152/