gruntjs - Grunt usemin 与模板

Question

给定以下目录结构:

– Gruntfile.js
– app
    |– index.php
    |– js
    |– css
    |– templates
         |– template.php
– dist

如何配置 grunt usemin 以更新模板文件中相对于使用模板的 index.php 的样式和脚本的引用？

目前的任务是这样的:

useminPrepare: {
    html: '<%= yeoman.app %>/templates/template.php',
    options: {
        dest: '<%= yeoman.dist %>'
    }
},
usemin: {
    html: ['<%= yeoman.dist %>/{,*/}*.php'],
    css: ['<%= yeoman.dist %>/css/*.css'],
    options: {
        dirs: ['<%= yeoman.dist %>']
    }
}

模板内部的块看起来像这样:

<!-- build:js js/main.js -->
    <script src="js/script1.js"></script>
    <script src="js/script2.js"></script>
<!-- endbuild -->

Answer 1

好吧，我发现了:
解决方案是使用备用搜索路径选项:

<!-- build:<type>(alternate search path) <path> -->
... HTML Markup, list of script / link tags.
<!-- endbuild -->

构建块现在看起来像这样:

<!-- build:js(app) js/main.js -->
    <script src="js/script1.js"></script>
    <script src="js/script2.js"></script>
<!-- endbuild -->

并且 usemin 任务配置如下:

usemin: {
    html: '<%= yeoman.dist %>/templates/template.php',
    css: ['<%= yeoman.dist %>/css/*.css'],
    options: {
        dirs: ['<%= yeoman.dist %>']
    }
}