scala - 为什么可变映射在 Spark 中的 UserDefinedAggregateFunction(UDAF) 中自动变为不可变

标签 scala apache-spark mutable user-defined-aggregate

我试图在 Spark 中定义一个 UserDefinedAggregateFunction(UDAF),它计算一个组列中每个唯一值的出现次数。

这是一个例子:
假设我有一个数据框 df像这样,

+----+----+
|col1|col2|
+----+----+
|   a|  a1|
|   a|  a1|
|   a|  a2|
|   b|  b1|
|   b|  b2|
|   b|  b3|
|   b|  b1|
|   b|  b1|
+----+----+

我将有一个 UDAF DistinctValues
val func = new DistinctValues

然后我将它应用到数据帧 df
val agg_value = df.groupBy("col1").agg(func(col("col2")).as("DV"))

我期待有这样的事情:
+----+--------------------------+
|col1|DV                        |
+----+--------------------------+
|   a|  Map(a1->2, a2->1)       |
|   b|  Map(b1->3, b2->1, b3->1)|
+----+--------------------------+

所以我想出了一个像这样的 UDAF,
import org.apache.spark.sql.expressions.MutableAggregationBuffer
import org.apache.spark.sql.expressions.UserDefinedAggregateFunction
import org.apache.spark.sql.Row
import org.apache.spark.sql.types.StructType
import org.apache.spark.sql.types.StructField
import org.apache.spark.sql.types.DataType
import org.apache.spark.sql.types.ArrayType
import org.apache.spark.sql.types.StringType
import org.apache.spark.sql.types.MapType
import org.apache.spark.sql.types.LongType
import Array._

class DistinctValues extends UserDefinedAggregateFunction {
  def inputSchema: org.apache.spark.sql.types.StructType = StructType(StructField("value", StringType) :: Nil)

  def bufferSchema: StructType = StructType(StructField("values", MapType(StringType, LongType))::Nil)

  def dataType: DataType =  MapType(StringType, LongType)
  def deterministic: Boolean = true

  def initialize(buffer: MutableAggregationBuffer): Unit = {
    buffer(0) = scala.collection.mutable.Map()
  }

  def update(buffer: MutableAggregationBuffer, input: Row) : Unit = {
    val str = input.getAs[String](0)
    var mp = buffer.getAs[scala.collection.mutable.Map[String, Long]](0)
    var c:Long = mp.getOrElse(str, 0)
    c = c + 1
    mp.put(str, c)
    buffer(0) = mp
  }

  def merge(buffer1: MutableAggregationBuffer, buffer2: Row) : Unit = {
    var mp1 = buffer1.getAs[scala.collection.mutable.Map[String, Long]](0)
    var mp2 = buffer2.getAs[scala.collection.mutable.Map[String, Long]](0)
    mp2 foreach {
        case (k ,v) => {
            var c:Long = mp1.getOrElse(k, 0)
            c = c + v
            mp1.put(k ,c)
        }
    }
    buffer1(0) = mp1
  }

  def evaluate(buffer: Row): Any = {
      buffer.getAs[scala.collection.mutable.Map[String, LongType]](0)
  }
}

然后我在我的数据框中有这个功能,
val func = new DistinctValues
val agg_values = df.groupBy("col1").agg(func(col("col2")).as("DV"))

它给出了这样的错误,
func: DistinctValues = $iwC$$iwC$DistinctValues@17f48a25
org.apache.spark.SparkException: Job aborted due to stage failure: Task 1 in stage 32.0 failed 4 times, most recent failure: Lost task 1.3 in stage 32.0 (TID 884, ip-172-31-22-166.ec2.internal): java.lang.ClassCastException: scala.collection.immutable.Map$EmptyMap$ cannot be cast to scala.collection.mutable.Map
at $iwC$$iwC$DistinctValues.update(<console>:39)
at org.apache.spark.sql.execution.aggregate.ScalaUDAF.update(udaf.scala:431)
at org.apache.spark.sql.execution.aggregate.AggregationIterator$$anonfun$12.apply(AggregationIterator.scala:187)
at org.apache.spark.sql.execution.aggregate.AggregationIterator$$anonfun$12.apply(AggregationIterator.scala:180)
at org.apache.spark.sql.execution.aggregate.SortBasedAggregationIterator.processCurrentSortedGroup(SortBasedAggregationIterator.scala:116)
at org.apache.spark.sql.execution.aggregate.SortBasedAggregationIterator.next(SortBasedAggregationIterator.scala:152)
at org.apache.spark.sql.execution.aggregate.SortBasedAggregationIterator.next(SortBasedAggregationIterator.scala:29)
at scala.collection.Iterator$$anon$11.next(Iterator.scala:328)
at scala.collection.Iterator$$anon$11.next(Iterator.scala:328)
at org.apache.spark.shuffle.sort.BypassMergeSortShuffleWriter.write(BypassMergeSortShuffleWriter.java:149)
at org.apache.spark.scheduler.ShuffleMapTask.runTask(ShuffleMapTask.scala:73)
at org.apache.spark.scheduler.ShuffleMapTask.runTask(ShuffleMapTask.scala:41)
at org.apache.spark.scheduler.Task.run(Task.scala:89)
at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:213)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at java.lang.Thread.run(Thread.java:745)

它看起来像在 update(buffer: MutableAggregationBuffer, input: Row)方法,变量 bufferimmutable.Map ,程序累把它投到mutable.Map ,

但我用了 mutable.Map初始化 buffer initialize(buffer: MutableAggregationBuffer, input:Row) 中的变量方法。是否与传递给 update 的变量相同?方法?还有buffermutableAggregationBuffer ,所以它应该是可变的,对吧?

为什么我的 mutable.Map 变得不可变?有谁知道发生了什么?

我真的需要这个函数中的可变 Map 来完成任务。我知道有一种解决方法可以从不可变映射创建可变映射,然后更新它。但是我真的很想知道为什么在程序中可变的会自动转换为不可变的,这对我来说没有意义。

最佳答案

相信是MapType在您的 StructType . buffer因此持有 Map ,这将是不可变的。

您可以转换它,但为什么不让它保持不变并执行以下操作:

mp = mp + (k -> c)

添加一个条目到不可变 Map ?

下面的工作示例:
class DistinctValues extends UserDefinedAggregateFunction {
  def inputSchema: org.apache.spark.sql.types.StructType = StructType(StructField("_2", IntegerType) :: Nil)

  def bufferSchema: StructType = StructType(StructField("values", MapType(StringType, LongType))::Nil)

  def dataType: DataType =  MapType(StringType, LongType)
  def deterministic: Boolean = true

  def initialize(buffer: MutableAggregationBuffer): Unit = {
    buffer(0) = Map()
  }

  def update(buffer: MutableAggregationBuffer, input: Row) : Unit = {
    val str = input.getAs[String](0)
    var mp = buffer.getAs[Map[String, Long]](0)
    var c:Long = mp.getOrElse(str, 0)
    c = c + 1
    mp = mp  + (str -> c)
    buffer(0) = mp
  }

  def merge(buffer1: MutableAggregationBuffer, buffer2: Row) : Unit = {
    var mp1 = buffer1.getAs[Map[String, Long]](0)
    var mp2 = buffer2.getAs[Map[String, Long]](0)
    mp2 foreach {
        case (k ,v) => {
            var c:Long = mp1.getOrElse(k, 0)
            c = c + v
            mp1 = mp1 + (k -> c)
        }
    }
    buffer1(0) = mp1
  }

  def evaluate(buffer: Row): Any = {
      buffer.getAs[Map[String, LongType]](0)
  }
}

关于scala - 为什么可变映射在 Spark 中的 UserDefinedAggregateFunction(UDAF) 中自动变为不可变,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36629916/

相关文章:

regex - scala 模式与正则表达式lookbehind 运算符匹配

java - 使用 java 8 Streams 从 DTO 中的数组列表中删除元素

scala - foldRight 过滤的 HList 不提供实例

scala - 使用 Scala Either,如何在第一个错误处停止,但获取已经计算的值

scala - 如何在 Spark 中强制执行 DataFrame 评估

database - 如何在分布式机器上划分一个非常大的单词列表搜索以获得更快的答案

apache-spark - 如何在 Spark DataFrame/DataSet 中将行拆分为不同的列?

C++ 语言一些可变的实例

python - 将 Pandas DataFrame 传递给函数的最佳实践

eclipse - Scala 2.8.1 和 Eclipse 中的延续