我有一个 data.frame,它有几个零值的变量。我需要构造一个额外的变量,它会返回每个观察值不为零的变量组合。例如。
df <- data.frame(firm = c("firm1", "firm2", "firm3", "firm4", "firm5"),
A = c(0, 0, 0, 1, 2),
B = c(0, 1, 0, 42, 0),
C = c(1, 1, 0, 0, 0))
现在我想生成新变量:
df$varCombination <- c("C", "B-C", NA, "A-B", "A")
我想到了这样的事情,这显然不起作用:
for (i in 1:nrow(df)){
df$varCombination[i] <- paste(names(df[i,2:ncol(df) & > 0]), collapse = "-")
}
最佳答案
这可能可以使用 apply(df, 1, fun)
轻松解决,但这里是为了性能而尝试解决这一列问题而不是行问题(我曾经看到@alexis_laz做过类似的事情,但现在找不到)
## Create a logical matrix
tmp <- df[-1] != 0
## or tmp <- sapply(df[-1], `!=`, 0)
## Prealocate result
res <- rep(NA, nrow(tmp))
## Run per column instead of per row
for(j in colnames(tmp)){
res[tmp[, j]] <- paste(res[tmp[, j]], j, sep = "-")
}
## Remove the pre-allocated `NA` values from non-NA entries
gsub("NA-", "", res, fixed = TRUE)
# [1] "C" "B-C" NA "A-B" "A"
在更大的数据集上的一些基准
set.seed(123)
BigDF <- as.data.frame(matrix(sample(0:1, 1e4, replace = TRUE), ncol = 10))
library(microbenchmark)
MM <- function(df) {
var_names <- names(df)[-1]
res <- character(nrow(df))
for (i in 1:nrow(df)){
non_zero_names <- var_names[df[i, -1] > 0]
res[i] <- paste(non_zero_names, collapse = '-')
}
res
}
ZX <- function(df) {
res <-
apply(df[,2:ncol(df)]>0, 1,
function(i)paste(colnames(df[, 2:ncol(df)])[i], collapse = "-"))
res[res == ""] <- NA
res
}
DA <- function(df) {
tmp <- df[-1] != 0
res <- rep(NA, nrow(tmp))
for(j in colnames(tmp)){
res[tmp[, j]] <- paste(res[tmp[, j]], j, sep = "-")
}
gsub("NA-", "", res, fixed = TRUE)
}
microbenchmark(MM(BigDF), ZX(BigDF), DA(BigDF))
# Unit: milliseconds
# expr min lq mean median uq max neval cld
# MM(BigDF) 239.36704 248.737408 253.159460 252.177439 255.144048 289.340528 100 c
# ZX(BigDF) 35.83482 37.617473 38.295425 38.022897 38.357285 76.619853 100 b
# DA(BigDF) 1.62682 1.662979 1.734723 1.735296 1.761695 2.725659 100 a
关于r - 如何在 R data.frame 中创建组合变量?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37273798/