问:如何根据 1 列的变化值对记录进行排名?
我有以下数据( https://pastebin.com/vdTb1JRT ):
EmployeeID Date Onleave
ABH12345 2016-01-01 0
ABH12345 2016-01-02 0
ABH12345 2016-01-03 0
ABH12345 2016-01-04 0
ABH12345 2016-01-05 0
ABH12345 2016-01-06 0
ABH12345 2016-01-07 0
ABH12345 2016-01-08 0
ABH12345 2016-01-09 0
ABH12345 2016-01-10 1
ABH12345 2016-01-11 1
ABH12345 2016-01-12 1
ABH12345 2016-01-13 1
ABH12345 2016-01-14 0
ABH12345 2016-01-15 0
ABH12345 2016-01-16 0
ABH12345 2016-01-17 0
我想产生以下结果:
EmployeeID DateValidFrom DateValidTo OnLeave
ABH12345 2016-01-01 2016-01-09 0
ABH12345 2016-01-10 2016-01-13 1
ABH12345 2016-01-14 2016-01-17 0
所以我在想我是否可以以某种方式创建一个排名列(如下所示),该列根据 Onleave 列中的值递增 - 由 EmployeeID 列分区。
EmployeeID Date Onleave RankedCol
ABH12345 2016-01-01 0 1
ABH12345 2016-01-02 0 1
ABH12345 2016-01-03 0 1
ABH12345 2016-01-04 0 1
ABH12345 2016-01-05 0 1
ABH12345 2016-01-06 0 1
ABH12345 2016-01-07 0 1
ABH12345 2016-01-08 0 1
ABH12345 2016-01-09 0 1
ABH12345 2016-01-10 1 2
ABH12345 2016-01-11 1 2
ABH12345 2016-01-12 1 2
ABH12345 2016-01-13 1 2
ABH12345 2016-01-14 0 3
ABH12345 2016-01-15 0 3
ABH12345 2016-01-16 0 3
ABH12345 2016-01-17 0 3
然后我将能够执行以下操作:
SELECT
[EmployeeID] = [EmployeeID]
,[DateValidFrom] = MIN([Date])
,[DateValidTo] = MAX([Date])
,[OnLeave] = [OnLeave]
FROM table/view/cte/sub-query
GROUP BY
[EmployeeID]
,[OnLeave]
,[RankedCol]
其他解决方案非常受欢迎..
以下是测试数据:
WITH CTE AS ( SELECT EmployeeID = 'ABH12345', [Date] = CAST(N'2016-01-01' AS Date), [Onleave] = 0
UNION SELECT 'ABH12345', CAST(N'2016-01-02' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-03' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-04' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-05' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-06' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-07' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-08' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-09' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-10' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-11' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-12' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-13' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-14' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-15' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-16' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-17' AS Date), 0
)
SELECT * FROM CTE
最佳答案
另一种方法是使用 lag
.通过获取每个员工 ID 的先前 Onleave 值并在找到不同值时重置它来分配组。
select employeeid,min(date) as date_from,max(date) as date_to,max(onleave) as onleave
from (select t.*,sum(case when prev_ol=onleave then 0 else 1 end) over(partition by employeeid order by date) as grp
from (select c.*,lag(onleave,1,onleave) over(partition by employeeid order by date) as prev_ol
from cte c
) t
) t
group by employeeid,grp
关于sql - 根据 1 列的变化值对记录进行排名,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44344690/