R - 基于匹配(模板)重新排序列

Question

所以我有一个看起来像这样的大数据集:

     V1       V2   V3         V4
1 Sleep Domestic  Eat Child Care
2 Sleep Domestic  Eat       Paid
3 Sleep Domestic  Eat Child Care
4 Sleep      Eat Paid       <NA>

我想做的是reorder基于"template"的列

["Sleep", "Eat", "Domestic", "Paid", "Child care"] 

得到(输出)

   V1    V2       V3      V4            V5
Sleep   Eat Domestic      NA    Child Care
Sleep   Eat Domestic    Paid            NA
Sleep   Eat Domestic      NA    Child Care
Sleep   Eat       NA    Paid            NA

所以在第 1 列 Sleep ，第 2 列 Eat , ...

我不知道从哪里开始。
任何的想法 ？

数据

x = structure(list(V1 = c("Sleep", "Sleep", "Sleep", "Sleep"), V2 = c("Domestic", 
"Domestic", "Domestic", "Eat"), V3 = c("Eat", "Eat", "Eat", "Paid"
), V4 = c("Child Care", "Paid", "Child Care", NA)), .Names = c("V1", 
"V2", "V3", "V4"), row.names = c(NA, 4L), class = "data.frame")

template = c('Sleep', 'Eat', 'Domestic', 'Paid', 'Child care')

Answer 1

检查 rowSums每个template值(value)，然后再次拼凑起来:

template <- c("Sleep", "Eat", "Domestic", "Paid", "Child Care")
# i've fixed this template so the case matches the values for 'Child Care'

data.frame(lapply(
  setNames(template, seq_along(template)),
  function(v) c(NA,v)[(rowSums(x==v,na.rm=TRUE)>0)+1]
))

#     X1  X2       X3   X4         X5
#1 Sleep Eat Domestic <NA> Child Care
#2 Sleep Eat Domestic Paid       <NA>
#3 Sleep Eat Domestic <NA> Child Care
#4 Sleep Eat     <NA> Paid       <NA>

或者使用 pmax 的替代方法:

data.frame(
  lapply(
    setNames(template, seq_along(template)), 
    function(v) do.call(pmax, c(replace(x, x != v,NA),na.rm=TRUE)) 
  )
)