android - 合并 spannable 对象时出错

Question

我想合并 3 个 spannable 对象。此代码工作正常:

Spannable s1 = new SpannableStringBuilder("bold");
             s1.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), 0, s1.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
             Spannable s2 = new SpannableStringBuilder("not");
             Spannable s3 = new SpannableStringBuilder("BOLD");
             s3.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), 0, s3.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
             finishSpan = (Spanned) TextUtils.concat(s1,s2);
             finishSpan = (Spanned) TextUtils.concat(finishSpan,s3);

///////////////////////////////////////////////////

或 finishSpan = (Spanned) TextUtils.concat(s1,s2,s3);

我有相同的代码，但是当我合并 3 个对象时，结果是错误的。 我已经检查了某些元素的类型是否正确。
beginningOfModifiedSpannable 为粗体，selectionSpannable 为普通，endOfModifiedSpannable 为粗体 但是他们的合并是错误的。只有结果字符串的最后部分是粗体。为什么会发生？？我在上面有相同的代码并且运行良好!

  Spannable str = contentText.getText();
            Spannable selectionSpannable = new SpannableStringBuilder(str, selectionStart, selectionEnd);
            StyleSpan[] ss = selectionSpannable.getSpans(0, selectionSpannable.length(), StyleSpan.class);

            boolean exists = false;
            for (int i = 0; i < ss.length; i++) {
                if (ss[i].getStyle() == android.graphics.Typeface.BOLD){
                 selectionSpannable.removeSpan(ss[i]);
                    exists = true;
                }
            }

            if (!exists){
                str.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), selectionStart, selectionEnd, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
            }
            else {

             Spannable endOfModifiedSpannable = new SpannableStringBuilder(str, selectionEnd, contentText.getText().length());
             Spannable beginningOfModifiedSpannable = new SpannableStringBuilder(str, 0, selectionStart);
             Spanned finishSpan = null;

             if(beginningOfModifiedSpannable.length() > 0) {

              if(endOfModifiedSpannable.length() > 0) {
               finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);
               finishSpan = (Spanned) TextUtils.concat(finishSpan,endOfModifiedSpannable);
                 }
              else {
               finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);
              }

             }
             else {
              if(endOfModifiedSpannable.length() > 0) {
               finishSpan = (Spanned) TextUtils.concat(selectionSpannable,endOfModifiedSpannable);
                     }
                  else {
                   finishSpan = selectionSpannable;
                  }
                 }
contentText.setText(finishSpan);

我再说一遍，我已经检查过 3 个部分都是真实的。例如。我有 3 个部分: 你好你好ld

我注意到第一次合并是正确的:

finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);

看起来像Hello,wor

但是第二个是错误的

finishSpan = (Spanned) TextUtils.concat(finishSpan,endOfModifiedSpannable);

或者这个合并是错误的:

finishSpan = (Spanned) TextUtils.concat(finishSpan,selectionSpannable,endOfModifiedSpannable);

错误字符串的结果是: 你好，我rld

但真正的结果一定是这样的:

你好你好，世界

废话!

Answer 1

问题是您很可能对第一个和第三个部分使用相同的 CharacterStyle 实例。每次向 Spannable 对象添加样式时都需要使用新实例。

例如

    SpannableStringBuilder ssb = new SpannableStringBuilder("Hello,world");
    CharacterStyle c = new StyleSpan(Typeface.BOLD);
    ssb.setSpan(c, 0, 3, 0);
    ssb.setSpan(c, 9, 11, 0);

这将导致 Hello,World

要获得正确的结果，您必须执行以下操作:

    SpannableStringBuilder ssb = new SpannableStringBuilder("Hello,world");
    CharacterStyle c = new StyleSpan(Typeface.BOLD);
    CharacterStyle c2 = new StyleSpan(Typeface.BOLD);
    ssb.setSpan(c, 0, 3, 0);
    ssb.setSpan(c2, 9, 11, 0);