post - 带有 Nginx 参数的 Laravel 为空

Question

我刚刚设置了 Nginx，我试图用它来托管 Laravel 应用程序，但我遇到了两个问题。

对于 GET 方法，我总是在我的输入中得到一个额外的参数。

使用 PostMan (Chrome) 进行测试，设置目标 URL 和所需参数并发送请求。我得到的输出，它总是包括 REQUEST_URI它不应该。示例输出:

.

Array (
  [/api/user] => // This shouldn't be here
  [test] => test
)

我的参数(以上)会不是 显示 DELETE 或 PUT，对于 POST 我只会得到 REQUEST_URI

Nginx 虚拟主机 (已关注 Setting up Laravel w/ Nginx)

server {
    server_name local.test.com;
    root /var/www/test/public;

    location / {
        index index.php index.html index.htm;
    }

    # serve static files directly
    location ~* \.(jpg|jpeg|gif|css|png|js|ico|html)$ {
        access_log off;
        expires max;
    }

    # removes trailing slashes (prevents SEO duplicate content issues)
    if (!-d $request_filename) {
        rewrite ^/(.+)/$ /$1 permanent;
    }

    # unless the request is for a valid file (image, js, css, etc.), send to bootstrap
    if (!-e $request_filename) {
        rewrite ^/(.*)$ /index.php?/$1 last;
        break;
    }

    # catch all
    error_page 404 /index.php;

    # The PHP Inclusion Block
    # include /etc/nginx/includes/php;
    location ~ \..*/.*\.php$ {
        # I'm pretty sure this stops people trying to traverse your site to get to other PHP files
        return 403;
    }

    #location ~ \.php$ {
    location ~ \.php(.*)$ {
        try_files $uri =404;
        fastcgi_split_path_info ^(.+\.php)(/.+)$;
        fastcgi_pass 127.0.0.1:9000;
        fastcgi_index index.php;
        include /etc/nginx/fastcgi_params;
    }

# Deny Any Access to .htaccess Files That May Be Present (not usually in issue in Laravel)
# include /etc/nginx/includes/deny_htaccess;
location ~ /\.ht
{
    deny all;
}

    error_log  /var/www/logs/test-error.log;
}

fastcgi_params :

fastcgi_param   QUERY_STRING            $query_string;
fastcgi_param   REQUEST_METHOD          $request_method;
fastcgi_param   CONTENT_TYPE            $content_type;
fastcgi_param   CONTENT_LENGTH          $content_length;

fastcgi_param   SCRIPT_FILENAME         $request_filename;
fastcgi_param   SCRIPT_NAME             $fastcgi_script_name;
fastcgi_param   REQUEST_URI             $request_uri;
fastcgi_param   DOCUMENT_URI            $document_uri;
fastcgi_param   DOCUMENT_ROOT           $document_root;
fastcgi_param   SERVER_PROTOCOL         $server_protocol;

fastcgi_param   GATEWAY_INTERFACE       CGI/1.1;
fastcgi_param   SERVER_SOFTWARE         nginx/$nginx_version;

fastcgi_param   REMOTE_ADDR             $remote_addr;
fastcgi_param   REMOTE_PORT             $remote_port;
fastcgi_param   SERVER_ADDR             $server_addr;
fastcgi_param   SERVER_PORT             $server_port;
fastcgi_param   SERVER_NAME             $server_name;

#fastcgi_param  HTTPS                   $https;

# PHP only, required if PHP was built with --enable-force-cgi-redirect
fastcgi_param   REDIRECT_STATUS         200;

fastcgi_connect_timeout                 60;
fastcgi_send_timeout                    180;
fastcgi_read_timeout                    180;
fastcgi_buffer_size                     128k;
fastcgi_buffers 4                       256k;
fastcgi_busy_buffers_size               256k;
fastcgi_temp_file_write_size            256k;
fastcgi_intercept_errors                on;

nginx.conf 只有一件事改变了，那就是 keepalive_timeout从 65 到 15

所以我完全不知道，这一切哪里出了问题。但我不得不提一下，在我拥有的另外 2 个环境(一个使用 Lighttpd，另一个使用 Apache2)上，该应用程序运行良好。

从我所注意到的，它都简化为以下代码:

# unless the request is for a valid file (image, js, css, etc.), send to bootstrap
if (!-e $request_filename) {
    rewrite ^/(.*)$ /index.php?/$1 last;
    break;
}

这将使 GET 工作......并添加附加参数

Answer 1

最好避免在您的 nginx 配置中进行不必要的重写(参见 Nginx Pitfalls)，特别是负责将请求传递给 Laravel 前端 Controller 的那个:

Laravel 所需要的只是:

location / {
    index index.php index.html index.htm;
    try_files $uri $uri/ index.php?$query_string;
}

首先尝试直接访问一个文件，然后是一个目录，如果两者都不存在，它将请求传递给 index.php。 $query_string重要的是传递，因为它将包含 $_GET否则会丢失的数据。

这是我自己的 FastCGI 配置部分:

location ~ \.php$ {
    fastcgi_pass   127.0.0.1:9000;
    fastcgi_index  index.php;
    fastcgi_param  SCRIPT_FILENAME    $document_root/$fastcgi_script_name;
    include        fastcgi_params;
}

至于意外输入，这可能是您当前重写的工作方式，但可以肯定地说，您输出的是什么？