json - 遍历嵌套的 JSON 对象并使用 Python 获取值

Question

我正在使用 Python；我需要遍历 JSON 对象并检索嵌套值。我的数据片段如下:

 "bills": [
{
  "url": "http:\/\/maplight.org\/us-congress\/bill\/110-hr-195\/233677",
  "jurisdiction": "us",
  "session": "110",
  "prefix": "H",
  "number": "195",
  "measure": "H.R. 195 (110\u003csup\u003eth\u003c\/sup\u003e)",
  "topic": "Seniors' Health Care Freedom Act of 2007",
  "last_update": "2011-08-29T20:47:44Z",
  "organizations": [
    {
      "organization_id": "22973",
      "name": "National Health Federation",
      "disposition": "support",
      "citation": "The National Health Federation (n.d.). \u003ca href=\"http:\/\/www.thenhf.com\/government_affairs_federal.html\"\u003e\u003ccite\u003e Federal Legislation on Consumer Health\u003c\/cite\u003e\u003c\/a\u003e. Retrieved August 6, 2008, from The National Health Federation.",
      "catcode": "J3000"
    },
    {
      "organization_id": "27059",
      "name": "A Christian Perspective on Health Issues",
      "disposition": "support",
      "citation": "A Christian Perspective on Health Issues (n.d.). \u003ca href=\"http:\/\/www.acpohi.ws\/page1.html\"\u003e\u003ccite\u003ePart E - Conclusion\u003c\/cite\u003e\u003c\/a\u003e. Retrieved August 6, 2008, from .",
      "catcode": "X7000"
    },
    {
      "organization_id": "27351",
      "name": "Natural Health Roundtable",
      "disposition": "support",
      "citation": "Natural Health Roundtable (n.d.). \u003ca href=\"http:\/\/naturalhealthroundtable.com\/reform_agenda\"\u003e\u003ccite\u003eNatural Health Roundtable SUPPORTS the following bills\u003c\/cite\u003e\u003c\/a\u003e. Retrieved August 6, 2008, from Natural Health Roundtable.",
      "catcode": "J3000"
    }
  ]
},

我需要通过“账单”中的每个对象并获得“ session ”、“前缀”等，我还需要通过每个“组织”并获得“名称”、“处置”等。我有以下代码:

import csv
import json

path = 'E:/Thesis/thesis_get_data'

with open (path + "/" + 'maplightdata110congress.json',"r") as f:
data = json.load(f)
a = data['bills']
b = data['bills'][0]["prefix"]
c = data['bills'][0]["number"]

h = data['bills'][0]['organizations'][0]
e = data['bills'][0]['organizations'][0]['name']
f = data['bills'][0]['organizations'][0]['catcode']
g = data['bills'][0]['organizations'][0]['catcode']

for i in a:
    for index in e:
          print ('name')

它会多次返回字符串“name”。

建议？

Answer 1

我在另一个论坛上找到了解决方案，并希望与这里的所有人分享，以防有人再次遇到这种情况。

import csv
import json

path = 'E:/Thesis/thesis_get_data'

with open (path + "/" + 'maplightdata110congress.json',"r") as f:
data = json.load(f)

for bill in data['bills']:
    for organization in bill['organizations']:
        print (organization.get('name'))`