我们发现了一些与感染有关的域名。现在,我们在.json文件中有了一个DNS名称列表,我想生成一个汇总输出,其中显示:用户列表,他们访问的唯一域,总数。如果我还可以获得每个域名的计数,则可获赠积分。
这是该文件的示例:
{"machine": "possible_victim01", "domain": "evil.com", "timestamp":1435071870}
{"machine": "possible_victim01", "domain": "evil.com", "timestamp":1435071875}
{"machine": "possible_victim01", "domain": "soevil.com", "timestamp":1435071877}
{"machine": "possible_victim02", "domain": "bad.com", "timestamp":1435071877}
{"machine": "possible_victim03", "domain": "soevil.com", "timestamp":1435071879}
理想情况下,我希望输出为:
{"possible_victim01": "total": 3, {"evil.com": 2, "soevil.com": 1}}
{"possible_victim02": "total": 1, {"bad.com": 1}}
{"possible_victim03": "total": 1, {"soevil.com": 1}}
我很乐意满足:
{"possible_victim01": "total": 3, ["evil.com", "soevil.com"]}
{"possible_victim02": "total": 1, ["bad.com"]}
{"possible_victim03": "total": 1, ["soevil.com"]}
我可以获得每个用户的记录总数,但是却丢失了域列表:
cat sample.json | jq -s 'group_by(.machine) | map({machine:.[0].machine,domain:.[0].domain, count:length}) '
[{"machine": "possible_victim01", "domain": "evil.com", "count": 3},
{"machine": "possible_victim02", "domain": "bad.com", "count": 1},
{"machine": "possible_victim03", "domain": "soevil.com", "count": 1}]
这篇文章描述了如何解决问题的后半部分... JQ Aggregations and Crosstabs。我还没有发现任何描述前半部分的内容,请转到:
{"machine": "possible_victim01", "domain": "evil.com", "count":2}
{"machine": "possible_victim01", "domain": "soevil.com", "count":1}
{"machine": "possible_victim02", "domain": "bad.com", "count":1}
{"machine": "possible_victim03", "domain": "soevil.com", "count":1}
最佳答案
您需要执行两次group_by
,一次按机器名称分组,然后再进行一次子分组以获取每个域的子计数。
jQuery查询:
group_by(.machine) | map({
"machine": .[0].machine,
"total":length,
"domains": (group_by(.domain) | map({
"key":.[0].domain,
"value":length}) | from_entries
)
})
输出示例:
{
"machine": "possible_victim01",
"total": 3,
"domains": {
"evil.com": 2,
"soevil.com": 1
}
}
{
"machine": "possible_victim02",
"total": 1,
"domains": {
"bad.com": 1
}
}
{
"machine": "possible_victim03",
"total": 1,
"domains": {
"soevil.com": 1
}
}
关于json - 使用jq进行多个级别的计数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31035704/