build - 如何从上次构建中获取输出目录？

Question

假设我有一个包含一个或多个项目的解决方案，并且我刚刚使用以下方法开始构建:

_dte.Solution.SolutionBuild.Build(true); // EnvDTE.DTE

如何获取刚刚构建的每个项目的输出路径？例如...

c:\MySolution\Project1\Bin\x86\Release\
c:\MySolution\Project2\Bin\Debug

Answer 1

请不要告诉我这是唯一的方法...

// dte is my wrapper; dte.Dte is EnvDte.DTE               
var ctxs = dte.Dte.Solution.SolutionBuild.ActiveConfiguration
              .SolutionContexts.OfType<SolutionContext>()
              .Where(x => x.ShouldBuild == true);
var temp = new List<string>(); // output filenames
// oh shi
foreach (var ctx in ctxs)
{
    // sorry, you'll have to OfType<Project>() on Projects (dte is my wrapper)
    // find my Project from the build context based on its name.  Vomit.
    var project = dte.Projects.First(x => x.FullName.EndsWith(ctx.ProjectName));
    // Combine the project's path (FullName == path???) with the 
    // OutputPath of the active configuration of that project
    var dir = System.IO.Path.Combine(
                        project.FullName,
                        project.ConfigurationManager.ActiveConfiguration
                        .Properties.Item("OutputPath").Value.ToString());
    // and combine it with the OutputFilename to get the assembly
    // or skip this and grab all files in the output directory
    var filename = System.IO.Path.Combine(
                        dir,
                        project.ConfigurationManager.ActiveConfiguration
                        .Properties.Item("OutputFilename").Value.ToString());
    temp.Add(filename);
}

这让我想干呕。