c - 使用 C scanf_s 输入字符串

Question

我一直试图自己寻找答案，但我找不到。
我想插入一部分程序，它读入像“Hello”这样的字符串并存储并可以在我想要的时候显示它，以便 printf("%s", blah);生产 Hello .

这是给我带来麻烦的代码部分

char name[64];
scanf_s("%s", name);
printf("Your name is %s", name);

我知道printf不是问题吗？在提示后输入内容后程序崩溃。请帮忙？

Answer 1

来自fscanf_s()的规范在 ISO/IEC 9899:2011 标准的附录 K.3.5.3.2 中:

The fscanf_s function is equivalent to fscanf except that the c, s, and [ conversion specifiers apply to a pair of arguments (unless assignment suppression is indicated by a *). The first of these arguments is the same as for fscanf. That argument is immediately followed in the argument list by the second argument, which has type rsize_t and gives the number of elements in the array pointed to by the first argument of the pair. If the first argument points to a scalar object, it is considered to be an array of one element.

和:

The scanf_s function is equivalent to fscanf_s with the argument stdin interposed before the arguments to scanf_s.

MSDN 说类似的话( scanf_s() 和 fscanf_s() )。

您的代码不提供长度参数，因此使用了其他一些数字。它无法确定它找到什么值，因此您会从代码中获得古怪的行为。您需要更像这样的东西，换行符有助于确保实际看到输出。

char name[64];
if (scanf_s("%s", name, sizeof(name)) == 1)
    printf("Your name is %s\n", name);