ruby-on-rails - rails : model scope filtered by instance method

Question

我有一个 Cover 模型，在 cover.rb 文件中，我还定义了一个名为 size 的方法，它返回一个表示“小、中、大”的整数。 我的问题是如何取回所有小号/中号/大号封面？ 我的猜测是使用 scope，但我不知道如何将 size 方法作为条件传递。

class Cover < ActiveRecord::Base
  attr_accessible :length, :width

  # TODO
  scope :small
  scope :intermediate
  scope :large

  # I have simplified the method for clarity.
  # 0 - small; 1 - intermediate;  2 - large
  def size
    std_length = std_width = 15
    if length < std_length && width < std_width
      0
    elsif length > std_length && width > std_width
      2
    else
      1
    end
  end

end

Answer 1

这可行:

class Cover < ActiveRecord::Base
  attr_accessible :length, :width

  scope :of_size, lambda{ |size| 
                          case size
                            when :small
                              where('width < 15 AND height < 15')
                            when :large
                              where('width > 15 AND height > 15')
                            when :intermediate
                              where('(width < 15 AND height > 15) OR (width > 15 AND height < 15)')
                            else
                              where(id: -1) # workaround to return empty AR::Relation
                        }

  def size
    std_length = std_width = 15
    return :small if length < std_length && width < std_width
    return :large if length > std_length && width > std_width
    return :intermediate
  end

end

然后像这样使用它:

Cover.of_size(:small) # => returns an array of Cover with size == small

要使其与多个参数一起工作:

# in the model:
scope :of_size, lambda{ |*size| all.select{ |cover| [size].flatten.include?(cover.size) } }
# how to call it:
Cover.of_size(:small, :large) # returns an array of covers with Large OR Small size