spring - Swagger codegen - 更改 api 和 Controller 类名称

Question

我正在尝试使用 swagger 为 spring 生成剩余代码。目前生成的api是V10Api.java，controller是V10ApiController.java。我希望自定义前缀为“ReadApi.java”和“ReadApiController.java”。

我看了解决方案here实现这个，所以我的代码是:

public class ReadApiSpringCodeGen extends SpringCodegen
{
    static {
        PREFIX="Read"; //compile error at PREFIX
    }
}

它在 PREFIX 处给出了编译错误，所以我猜测 PREFIX 不在父类(super class)中。

我修改了类以结束 toApiName() 方法:

public class ReadApiSpringCodeGen extends SpringCodegen
{
    @Override
    public String toApiName(String name) {
        System.out.println("Name in is ["+name+"]");
        if (name.length() == 0) {
            return "DefaultApi";
        }
        name = sanitizeName(name);
        return camelize(name) + "Read";
    }

   public static void main(String[] args)
   {
       System.out.println("Main called");
   }
}

当运行代码生成器时:

${JAVA_HOME}/bin/java -cp .:./swagger-codegen-cli-2.2.1.jar \
-jar swagger-codegen-cli-2.2.1.jar generate \
    -i Read.yaml \
    -l com.foo.swag.codegen.swagger.ReadApiSpringCodeGen \
....

我得到错误:

Exception in thread "main" java.lang.RuntimeException: Can't load config class with name com.foo.swag.codegen.swagger.ReadApiSpringCodeGen Available: android
ndroid
aspnet5
async-scala
cwiki
csharp
cpprest
.....
at io.swagger.codegen.CodegenConfigLoader.forName(CodegenConfigLoader.java:31)
at io.swagger.codegen.config.CodegenConfigurator.toClientOptInput(CodegenConfigurator.java:353)
at io.swagger.codegen.cmd.Generate.run(Generate.java:221)
at io.swagger.codegen.SwaggerCodegen.main(SwaggerCodegen.java:36)
Caused by: java.lang.ClassNotFoundException: com.foo.swag.codegen.swagger.ReadApiSpringCodeGen
at java.net.URLClassLoader.findClass(URLClassLoader.java:381)
at java.lang.ClassLoader.loadClass(ClassLoader.java:424)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:331)
at java.lang.ClassLoader.loadClass(ClassLoader.java:357)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Class.java:264)
at io.swagger.codegen.CodegenConfigLoader.forName(CodegenConfigLoader.java:29)
... 3 more

Answer 1

你必须覆盖方法 apiFilename - 像这样:

@Override
public String apiFilename(final String templateName, final String tag) {
    final String pathWithFile = super.apiFilename(templateName, tag);
    final String pathWithoutFileExtension = pathWithFile.substring(0, pathWithFile.lastIndexOf('.')); //without .java
    final int index = pathWithoutFileExtension.lastIndexOf('.');
    final String className = ".Read" + pathWithoutFileExtension.substring(index+1) + ".java";
    result pathWithoutFileExtension.substring(0, pathWithoutFileExtension.lastIndexOf('.')) + className;
}