ruby-on-rails - Scala(任何框架)中是否有像 Rails 中的脚手架这样的 CRUD 生成器实用程序？

Question

参见:Is there a CRUD generator utility in Java(any framework) like Scaffolding in Rails?

我有同样的问题，但关于 Scala。我知道 Play 框架 1.x 有生成器，但 2.x 删除了它们，是否有适用于任何基于 Scala 的 Web 框架的有效 CRUD/脚手架生成器？

Answer 1

我也在寻找一个脚手架工具(它弹出了你的问题)并找到了这个:http://skinny-framework.org/documentation/scaffolding.html

我还没有尝试过，但文档看起来可以完成这项工作:

./skinny g 模型 tweet userId:Long text:String user:Option[User] 将创建

package model

import skinny.orm._, feature._
import scalikejdbc._
import org.joda.time._

// If your model has +23 fields, switch this to normal class and mixin scalikejdbc.EntityEquality.
case class Tweet(
  id: Long,
  userId: Long,
  text: String,
  user: Option[User] = None,
  createdAt: DateTime,
  updatedAt: DateTime
)

object Tweet extends SkinnyCRUDMapper[Tweet] with TimestampsFeature[Tweet] {

  override lazy val defaultAlias = createAlias("t")

  lazy val userRef = belongsTo[User](User, (t, u) => t.copy(user = u))

  /*
   * If you're familiar with ScalikeJDBC/Skinny ORM, using #autoConstruct makes your mapper simpler.
   * (e.g.)
   * override def extract(rs: WrappedResultSet, rn: ResultName[Tweet]) = autoConstruct(rs, rn)
   *
   * Be aware of excluding associations like this:
   * (e.g.)
   * case class Member(id: Long, companyId: Long, company: Option[Company] = None)
   * object Member extends SkinnyCRUDMapper[Member] {
   *   override def extract(rs: WrappedResultSet, rn: ResultName[Member]) =
   *     autoConstruct(rs, rn, "company") // "company" will be skipped
   * }
   */
  override def extract(rs: WrappedResultSet, rn: ResultName[Tweet]): Tweet = new Tweet(
    id = rs.get(rn.id),
    userId = rs.get(rn.userId),
    text = rs.get(rn.text),
    createdAt = rs.get(rn.createdAt),
    updatedAt = rs.get(rn.updatedAt)
  )
}

希望这对您有所帮助!