drupal-7 - EntityFieldQuery 多个备选条件

Question

是否有更优化和更短的方法来获得特定条件的节点？

$query = new EntityFieldQuery;
$result = $query
  ->entityCondition('entity_type', 'node')
  ->propertyCondition('type', $node_type)
  ->propertyCondition('title', $title)
  ->fieldCondition('field_number', 'value', '1', '=');
  ->propertyCondition('status', 1, '=')
  ->execute();

// $result['node'] contains a list of nids where the title matches
if (!empty($result['node']) {
  // You could use node_load_multiple() instead of entity_load() for nodes
  $nodes = entity_load('node', array_keys($result['node']));
}

$query_two = new EntityFieldQuery;
$result_two = $query_two
  ->entityCondition('entity_type', 'node')
  ->propertyCondition('type', $node_type)
  ->propertyCondition('title', $title)
  ->fieldCondition('field_number', 'value', '2', '=');
  ->propertyCondition('status', 1, '=')
  ->execute();

// $result_two['node'] contains a list of nids where the title matches
if (!empty($result_two['node']) {
  // You could use node_load_multiple() instead of entity_load() for nodes
  $nodes_two = entity_load('node', array_keys($result_two['node']));
}

Answer 1

那么，你当然可以使用 ->fieldCondition('field_number', 'value', array(1, 2)) ，但除此之外，我不知道(我写了 EntityFieldQuery )。即使您将其重写为仅用于 SQL 存储的查询，也不会简单得多。

您不需要指定 =作为运算符，您无需指定 IN或者，它们是标量/数组值的默认值。