我正在尝试使用以下代码在 Django 中实现抽象继承,但它会产生 MAX 递归深度错误。我正在尝试覆盖模型的 save
方法。
class BaseModel(models.Model):
class Meta:
abstract = True
def save(self, *args, **kwargs):
#i'm doing something here
#i think the problem is in the return statement specifically because of the
#self.__class__ expression.
return super(self.__class__, self).save(*args, **kwargs)
class MyModel(BaseModel):
p = models.CharField(max_length=30)
产生此错误(跟踪结束,很长):
File "/home/jultra/ap3w/jultra_01/mysite/testsite/models.py", line 10, in save
return super(self.__class__, self).save(*args, **kwargs)
File "/home/jultra/ap3w/jultra_01/mysite/testsite/models.py", line 10, in save
return super(self.__class__, self).save(*args, **kwargs)
File "/home/jultra/ap3w/jultra_01/mysite/testsite/models.py", line 10, in save
return super(self.__class__, self).save(*args, **kwargs)
File "/home/jultra/ap3w/jultra_01/mysite/testsite/models.py", line 10, in save
return super(self.__class__, self).save(*args, **kwargs)
RuntimeError: maximum recursion depth exceeded
最佳答案
做 不是 调用 super
在 self.__class__
!在实际类上调用它:
return super(BaseModel, self).save(*args, **kwargs)
这是因为
self.__class__
总是指实例的实际具体类。所以如果你继承MyModel
来自 BaseModel
,当您到达 save
时BaseModel
中的方法self.__class__
还在MyModel
.于是找到了MyModel的super,也就是BaseModel,于是调用了BaseModel中的save,又一次找到了MyModel的super……
关于django - Django Model中的抽象继承,导致MAX递归深度错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10948132/