spring - 在RxJava Services中管理事务性的正确方法是什么?

标签 spring reactive-programming rx-java rx-android netflix

我最近开始尝试RxJava,并遇到了一位Netflix工程师的演讲,该演讲建议将我们的业务API迁移到Observable API,例如:

public interface VideoService {
    Observable<VideoBasicInfo> createVideoBasicInfo(VideoBasicInfo videoBasic);
    Observable<VideoBasicInfo> getVideoBasicInfo(Integer videoId);
    Observable<VideoRating> getVideoRating(Integer videoId);
}

但是,我还没有找到任何地方可以解释如何在此服务中管理事务性。起初,我只是用@Transactional注释了我的服务实现
@Service
@Transactional
public class VideoServiceImpl implements VideoService{

    @Autowired
    private VideoBasicInfoRepository basicInfoRepo;
    @Autowired
    private VideoRatingRepository ratingRepo;

    public Observable<VideoBasicInfo> createVideoBasicInfo(VideoBasicInfo videoBasic){
        return Observable.create( s -> {
            s.onNext(basicInfoRepo.save(videBasic));
        });
    }

我们想要的是Object.create lambda(s -> { // This code })内部的所有代码的执行都在事务中发生。 但是,实际发生的是:
  • createVideoBasicInfo()的调用以事务方式执行,返回可观察到的寒冷。
  • save()作为原子事务执行。

  • 显然,这是有道理的,因为Spring代理适用于serviceImpl方法。我已经想到了一些可以实现自己真正期望的方法,例如启动程序化事务:
    return Observable.create( s -> {
        VideoBasicInfo savedBasic = transactionTemplate.execute( status -> {
            VideoBasicInfo basicInfo = basicInfoRepo.save(videoBasicInfo);
            return basicInfo;
        });
        s.onNext(savedBasic);
    });
    

    在使用响应式(Reactive)API时,这是推荐的管理事务的方法吗?

    最佳答案

    Spring Data JpaRepository方法签名已经标记为@Transactional,因此,如果仅使用一个,则无需执行任何特殊操作:

    public interface PersonRepository extends JpaRepository<Person, Integer> {
    }
    
    @RunWith(SpringJUnit4ClassRunner.class)
    @SpringApplicationConfiguration(classes = {RepositoryConfiguration.class})
    public class PersonRepositoryTest {
        private PersonRepository personRepository;
    
        @Autowired
        public void setPersonRepository(PersonRepository PersonRepository) {
            this.personRepository = PersonRepository;
        }
    
        @Test
        public void testReactiveSavePerson() {
            Person person = new Person("Jane", "Doe");
            assertNull(person.getId()); //null before save
    
            //save person
            Observable.create(s -> {
                s.onNext(personRepository.save(person));
            }).subscribe();
    
            //fetch from DB
            Person fetchedPerson = personRepository.findOne(person.getId());
    
            //should not be null
            assertNotNull(fetchedPerson);
    
            //should equal
            assertEquals(person.getId(), fetchedPerson.getId());
            assertEquals(person.getFirstName(), fetchedPerson.getFirstName());
        }
    }
    

    如果需要将多个存储库合并到一个事务中,则可以使用下面的类:
    @Component()
    public class ObservableTxFactory {
        public final <T> Observable<T> create(Observable.OnSubscribe<T> f) {
            return new ObservableTx<>(this, f);
        }
    
        @Transactional
        public void call(Observable.OnSubscribe onSubscribe, Subscriber subscriber) {
            onSubscribe.call(subscriber);
        }
    
        private static class ObservableTx<T> extends Observable<T> {
    
            public ObservableTx(ObservableTxFactory observableTxFactory, OnSubscribe<T> f) {
                super(new OnSubscribeDecorator<>(observableTxFactory, f));
            }
        }
    
        private static class OnSubscribeDecorator<T> implements Observable.OnSubscribe<T> {
    
            private final ObservableTxFactory observableTxFactory;
            private final Observable.OnSubscribe<T> onSubscribe;
    
            OnSubscribeDecorator(final ObservableTxFactory observableTxFactory, final Observable.OnSubscribe<T> s) {
                this.onSubscribe = s;
                this.observableTxFactory = observableTxFactory;
            }
    
            @Override
            public void call(Subscriber<? super T> subscriber) {
                observableTxFactory.call(onSubscribe, subscriber);
            }
        }
    }
    

    还需要定义工厂bean:
    @Bean
    ObservableTxFactory observableTxFactory() {
        return new ObservableTxFactory();
    }
    

    服务:
    @Service
    public class PersonService {
        @Autowired
        PersonRepository personRepository;
        @Autowired
        ObservableTxFactory observableTxFactory;
    
        public Observable<Person> createPerson(String firstName, String lastName) {
            return observableTxFactory.create(s -> {
                Person p = new Person(firstName, lastName);
                s.onNext(personRepository.save(p));
            });
        }
    }
    

    测试:
    @RunWith(SpringJUnit4ClassRunner.class)
    @SpringApplicationConfiguration(classes = {RepositoryConfiguration.class})
    public class PersonServiceTest {
        @Autowired
        PersonRepository personRepository;
        @Autowired
        ObservableTxFactory observableTxFactory;
    
        @Test
        public void testPersonService() {
            final PersonService service = new PersonService();
            service.personRepository = personRepository;
            service.observableTxFactory = observableTxFactory;
    
            final Observable<Person> personObservable = service.createPerson("John", "Doe");
            personObservable.subscribe();
    
            //fetch from DB
            final Person fetchedPerson = StreamSupport.stream(personRepository.findAll().spliterator(), false)
                    .filter(p -> p.getFirstName().equals("John") && p.getLastName().equals("Doe"))
                    .findFirst()
                    .get();
    
            //should not be null
            assertNotNull(fetchedPerson);
        }
    
    }
    

    屏幕截图显示了代理:
    enter image description here

    关于spring - 在RxJava Services中管理事务性的正确方法是什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34250741/

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