ruby-on-rails - 如何强制Rails查询为每个结果返回两个可能的模型？

Question

我正在使用Rails5。我在 Controller 模型中具有此功能，可以根据条件加载特定模型...

  @results = MyObjectTime.joins(:my_object,
                            "LEFT JOIN user_my_object_time_matches on my_object_times.id = user_my_object_time_matches.my_object_time_id #{additional_left_join_clause}")
                     .where( search_criteria.join(' and '), *search_values )
                     .limit(1000) 
                     .order("my_objects.day DESC, my_objects.name")
                     .paginate(:page => params[:page])

我的问题是，如何重写以上内容，以便@results数组同时包含“MyObjectTime”和与其链接的任何潜在“UserMyObjectTimeMatch”？

Answer 1

我建议搜索一种替代方法，但是如果您具有has_many'user_my_object_time_matches'设置，则可以利用您提供的信息并避免在注释中提及潜在的10001查询:

@results = MyObjectTime.joins(:my_object,
                            "LEFT JOIN user_my_object_time_matches on my_object_times.id = user_my_object_time_matches.my_object_time_id #{additional_left_join_clause}")
        .where( search_criteria.join(' and '), *search_values )
        .limit(1000) 
        .order("my_objects.day DESC, my_objects.name")
        .paginate(:page => params[:page])
        .includes(:user_my_object_time_matches)
        .map{|t| [t, t.user_my_object_time_matches]}