确定因素或基于许多 bool 字段创建新类别字段的最佳方法是什么?在此示例中,我需要计算药物的唯一组合数。
> MultPsychMeds
ID OLANZAPINE HALOPERIDOL QUETIAPINE RISPERIDONE
1 A 1 1 0 0
2 B 1 0 1 0
3 C 1 0 1 0
4 D 1 0 1 0
5 E 1 0 0 1
6 F 1 0 0 1
7 G 1 0 0 1
8 H 1 0 0 1
9 I 0 1 1 0
10 J 0 1 1 0
也许另一种表达方式是我需要对或对列表进行交叉或交叉制表。最终结果应类似于:
Combination Count
OLANZAPINE/HALOPERIDOL 1
OLANZAPINE/QUETIAPINE 3
OLANZAPINE/RISPERIDONE 4
HALOPERIDOL/QUETIAPINE 2
可以使用以下命令在R中复制此数据帧:
MultPsychMeds <- structure(list(ID = structure(1:10, .Label = c("A", "B", "C",
"D", "E", "F", "G", "H", "I", "J"), class = "factor"), OLANZAPINE = c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 0L, 0L), HALOPERIDOL = c(1L, 0L,
0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L), QUETIAPINE = c(0L, 1L, 1L, 1L,
0L, 0L, 0L, 0L, 1L, 1L), RISPERIDONE = c(0L, 0L, 0L, 0L, 1L,
1L, 1L, 1L, 0L, 0L)), .Names = c("ID", "OLANZAPINE", "HALOPERIDOL",
"QUETIAPINE", "RISPERIDONE"), class = "data.frame", row.names = c(NA,
-10L))
最佳答案
这是使用reshape
和plyr
包的一种方法:
library(reshape)
library(plyr)
#Melt into long format
dat.m <- melt(MultPsychMeds, id.vars = "ID")
#Group at the ID level and paste the drugs together with "/"
out <- ddply(dat.m, "ID", summarize, combos = paste(variable[value == 1], collapse = "/"))
#Calculate a table
with(out, count(combos))
x freq
1 HALOPERIDOL/QUETIAPINE 2
2 OLANZAPINE/HALOPERIDOL 1
3 OLANZAPINE/QUETIAPINE 3
4 OLANZAPINE/RISPERIDONE 4
关于r - 如何计算R中 bool 数据的组合数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7184950/