objective-c - Objective-C 中的 @ 运算符是否与 C 中的 & 运算符相同？

Question

Objective C 的新手。尝试理解 Objective C 中的指针。

我的代码

#import <Foundation/Foundation.h>

 int main (int argc, const char * argv[]) {

    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];

NSString *msg = @"Hello Bhai";
NSLog(@" address is %i for msg", msg);
NSLog(@" which is same address  %i for Hello Bhai", @"Hello Bhai");
NSLog(@" which is different address  %i for Hello mere Bhai", @"Hello mere Bhai");
NSLog(@" value is %@ at the address for msg", msg);


[pool drain];
    return 0;
}

输出是

[Session started at 2011-04-26 16:31:11 -0400.]
2011-04-26 16:31:11.656 BasicObjC[1523:10b]  address is 8240 for msg
2011-04-26 16:31:11.658 BasicObjC[1523:10b]  which is same address  8240 for Hello Bhai
2011-04-26 16:31:11.659 BasicObjC[1523:10b]  which is different address  8288 for Hello mere Bhai
2011-04-26 16:31:11.660 BasicObjC[1523:10b]  value is Hello Bhai at the address for msg

这是否意味着 Objective C 中的 @ 与 C 中的 & 相同

Answer 1

@ 用于表示字符串是 NSString 文字，因此您可以将其分配给 NSString 对象。

如果你想打印一些地址，那么你应该使用 %p 格式说明符，而不是 %i，例如

NSLog(@" address is %p for msg", msg);